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I am Lyosha [343]
3 years ago
5

What must be true of a disproportionate substance?

Chemistry
2 answers:
Taya2010 [7]3 years ago
8 0
D. It gains and loses electrons
Rudik [331]3 years ago
4 0

Answer:

Answer is D.it gains and loses electrons.

Explanation:

I hope it's helpful!

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In the following equation,
Nina [5.8K]
It is C It is C It is C
3 0
3 years ago
The following reaction has an activation energy of 262 kJ/mol.
Hitman42 [59]

Answer: i really       dont know srry

Explanation:

4 0
3 years ago
Brass is a substitutional alloy consisting of a solution of copper and zinc. A particular sample of red brass consisting of 79.0
Bas_tet [7]

<u>Answer:</u> The molality and molarity of zinc in the solution is 4.07 m and 28.11 M respectively.

<u>Explanation:</u>

Solute is the substance which is present in smaller proportion in a mixture and solvent is the substance which is present in larger proportion in a mixture.

We are given:

(m/m) % of Cu = 79 %

This means that 79 g of copper is present in 100 grams of alloy.

(m/m) % of Zn = 21 %

This means that 21 g of zinc is present in 100 grams of alloy.

As, zinc is present in smaller proportion. So, it is solute and copper is the solvent.

  • <u>Calculating molality of zinc:</u>

To calculate molality of the zinc, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

m_{solute} = Given mass of solute (Zinc ) = 21 g

M_{solute} = Molar mass of solute (Zinc) = 65.3 g/mol

W_{solvent} = Mass of solvent (copper) = 79 g

Putting values in above equation, we get:

\text{Molality of Zinc}=\frac{21\times 1000}{65.3\times 79}\\\\\text{Molality of zinc}=4.07m

  • <u>Calculating molarity of zinc:</u>

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 8740kg/m^3=\frac{8740kg\frac{1000g}{1kg}}{1m^3\times \frac{10^6cm^3}{1m^3}}=\frac{8740g}{1000cm^3}=8.740g/cm^3

(Conversion factors used are:  1 kg = 1000 g &  1m^3=10^6cm^3  )

Mass of solution = 100 g

Putting values in above equation, we get:

8.740g/cm^3=\frac{100.0g}{\text{Volume of zinc}}\\\\\text{Volume of zinc}=11.44cm^3

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molar mass of zinc = 65.3 g/mol

Volume of solution = 11.44cm^3=11.44mL     (Conversion factor:  1cm^3=1mL  )

Mass of zinc = 21.0 g

Putting values in above equation, we get:

\text{Molarity of zinc}=\frac{21\times 1000}{65.3\times 11.44}=28.11M

Hence, the molality and molarity of zinc in the solution is 4.07 m and 28.11 M respectively.

4 0
4 years ago
Which two changes would increase the gravitational force between two
scoundrel [369]

Answer:

B. Increase the mass of one of the objects.

E. Decrease the distance between the objects.

Explanation:

To effect an increase in the gravitational force between two objects, the mass of both objects should be increased and the distance between them reduced.

This is derived from the Newton's law of universal gravitation:

  • It states that "the force of gravity between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them".

Therefore, if the mass of the two bodies are increased and the distance between them reduced, the gravitational force of attraction will increase.

4 0
3 years ago
The following reaction plays a key role in the destruction of ozone In the atmosphere:
lys-0071 [83]

Answer:

19.91 J/K

Explanation:

The entropy is a measure of the randomness of the system, and it intends to increase in nature, thus for a spontaneous reaction ΔS > 0.

The entropy variation can be found by:

ΔS = ∑n*S° products - ∑n*S° reactants

Where n is the coefficient of the substance. The value of S° (standard molar entropy) can be found at a thermodynamic table.

S°, Cl(g) = 165.20 J/mol.K

S°, O3(g) = 238.93 J/mol.K

S°, O2(g) = 205.138 J/mol.K

So:

ΔS = (1*205.138 + 1*218.9) - (1*165.20 + 1*238.93)

ΔS = 19.91 J/K

6 0
4 years ago
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