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torisob [31]
3 years ago
8

On June 23, which area will sunlight hit more directly?

Physics
1 answer:
Julli [10]3 years ago
8 0
<span>At any particular time of day on June 23, sunlight will fall on the
northern hemisphere more directly than the southern hemisphere,
and on the north pole more directly than the south pole. (In fact,
at that time, the south pole will be halfway through a 6-month period
of no sunlight at all.) 

On June 23, the sun will appear to be directly over the parallel
of 23.5</span>° north latitude<span>, or nearly so ... the farthest north that the
sun ever appears to be.</span>
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Lilit [14]

Answer:

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3 years ago
Which statement most completely describes a Lewis electron dot diagram? A.
andrezito [222]

Answer:

i do not know

Explanation:

5 0
2 years ago
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A wave has a wavelength of 3.0 m, a frequency of 25.0 Hz, and an amplitude of 14.0 cm. The wave travels in the positive x-direct
Mrac [35]

Answer:

The total number of oscillations made by the wave during the time of travel is 1.4 Oscillations. Strictly speaking, the number of complete oscillations is 1.

Explanation:

The required quantity is the number of complete oscillations made by the traveling wave. The amplitude time and frequency are not needed to calculate the number of oscillations as it is the ratio of the distance traveled to the wavelength( minimum distance that must be traveled to complete one oscillation) of the wave. So the total number of oscillations is 1.4 while the number of complete oscillations is 1 (strictly speaking). The detailed solution to this question can be found in the attachment below. Thank you!

4 0
3 years ago
The photon energies used in different types of medical x-ray imaging vary widely, depending upon the application. Single dental
pav-90 [236]

A) 5.0\cdot 10^{-11} m

The energy of an x-ray photon used for single dental x-rays is

E=25 keV = 25,000 eV \cdot (1.6\cdot 10^{-19} J/eV)=4\cdot 10^{-15} J

The energy of a photon is related to its wavelength by the equation

E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34}Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

Re-arranging the equation for the wavelength, we find

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15}J}=5.0\cdot 10^{-11} m

B) 2.0\cdot 10^{-11} m

The energy of an x-ray photon used in microtomography is 2.5 times greater than the energy of the photon used in part A), so its energy is

E=2.5 \cdot (4\cdot 10^{-15}J)=1\cdot 10^{-14} J

And so, by using the same formula we used in part A), we can calculate the corresponding wavelength:

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14}J}=2.0\cdot 10^{-11} m

4 0
3 years ago
In the equation Ca(s) + 2H2O(l) --&gt;Ca(OH)2(aq) + H2(g) list each element used as a reactant, and tell how many atoms of each
Mekhanik [1.2K]

The reactants are <em>Calcium</em>, <em>Hydrogen</em> and <em>Oxygen</em>.

We need 1 atom of <em>Calcium</em>, 4 atoms of <em>Hydrogen</em> and 2 atoms of <em>Oxygen</em>.

Hope this helps.

r3t40

3 0
3 years ago
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