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torisob [31]
3 years ago
8

On June 23, which area will sunlight hit more directly?

Physics
1 answer:
Julli [10]3 years ago
8 0
<span>At any particular time of day on June 23, sunlight will fall on the
northern hemisphere more directly than the southern hemisphere,
and on the north pole more directly than the south pole. (In fact,
at that time, the south pole will be halfway through a 6-month period
of no sunlight at all.) 

On June 23, the sun will appear to be directly over the parallel
of 23.5</span>° north latitude<span>, or nearly so ... the farthest north that the
sun ever appears to be.</span>
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If a girl carries groceries up a flight of stairs, is she doing work on the groceries? Explain.​
nikdorinn [45]

Answer:

Explanation:

Yes she is doing work. With or without the groceries, she is still doing work. She does more work with the groceries than without because Work is defined by F which is defined by mass. The mass increases with the groceries.

The work done is against the force of gravity.

4 0
3 years ago
A SMA wire in the un-stretched condition is then given an initial strain of εo (to preload the wire) at room temperature (RT). I
julia-pushkina [17]

Answer: tensional force

Explanation:

Tension force on a material occurs when two equal forces act on a material in an opposite direction away from the ends of the material.

Pre-tensing a wire material increases its load bearing capacity and reduces its flexure.

6 0
3 years ago
State the name given to the energy that is needed to melt the ice cube: latent __________.
Vaselesa [24]

Answer:

Explanation: heat of fusion

5 0
3 years ago
A rectangular field is 300 meters long and 300 meters wide. What is the area of the field in square kilometers? Do not round you
dexar [7]

Answer:

Area of the rectangular field in kilometers is 0.09 km^2

Explanation:

We know that 1 kilometers = 1000 meters

                    since we need to find the area in unit of kilometers

                    therefore converting length and width into kilometers

           1000 meters = 1 kilometers

             300 meters =\frac{300}{1000} = 0.3

         Likewise  width  = 0.3 km

Area = length x width

         = 0.3km x 0.3 km

        = 0.09 km^2

       

6 0
3 years ago
A particle with a charge of 5 × 10–6 C and a mass of 20 g moves uniformly with a speed of 7 m/s in a circular orbit around a sta
creativ13 [48]

Answer:

r = 0.22m

Explanation:

To find the radius of the circular trajectory, you first take into account that the centripetal force of the charged particle, is equal to the electric force between the particle that is moving and the particle at the center of the orbit.

Then, you have:

F_c=F_e=ma_c      (1)

m: mass of the particle = 20g = 20*10-3 kg

ac: centripetal acceleration = ?

q: charge of the particle = 5*10^-6C

Fe: electric force between the charges

The electric force is given by:

F_e=k\frac{qq'}{r^2}             (2)

r: radius of the orbit

q': charge of the particle at the center of the orbit = -5*10^-6C

Furthermore, the centripetal acceleration is:

a_c=\frac{v^2}{r}                 (3)

v: speed of the particle = 7m/s

You replace the expressions (2) and (3) in the equation (1) and solve for r:

k\frac{qq'}{r^2}=m\frac{v^2}{r}\\\\r=\frac{kqq'}{mv^2}

Finally, you replace the values of all parameters in the previous expression:

r=\frac{(8.98*10^9Nm^2/C^2)(5*10^{-6}C)(5*10^{-6}C)}{(20*10^{-3}kg)(7m/s)^2}\\\\r=0.22m

The radius of the circular trajectory is 0.22m

5 0
3 years ago
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