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earnstyle [38]
3 years ago
13

the object on the right gained mass so that it had as much mass as the object on the left, how would the gravitational force bet

ween them change? Also, assume the distance between the centers of the objects stayed constant. A. It would increase. B. It would decrease. C. It would remain the same.
Physics
2 answers:
slamgirl [31]3 years ago
7 0

Answer:

a

Explanation:

kherson [118]3 years ago
6 0

The gravitational force between the objects A. It would increase.

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m_1,m_2 are the masses of the two objects

r is the separation between the objects

In this problem, we are told that one of the object (the one on the right) gains mass: this means that, for instance, the value of m_2 increases. We can see from the equation that the gravitational force is directly proportional to the masses: therefore, if one of the masses increases (while the distance between the two objects remains constant), it means that the force also increases.

Therefore, the correct answer is

A. It would increase.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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Nutka1998 [239]
The answer is 2.6m/s2
7 0
3 years ago
Any Help??? Dued before 2:30pm and it's 9:30am by me... so please take yuh time and ans.... jus ans 1 if you want... This is for
Kryger [21]

Answer:

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5 0
3 years ago
I need help ASAP plzzzz
Fiesta28 [93]

Answer:

a) 1.75s b) 17.2 m/s (down)

Explanation:

d1= 15m d2= 0m (because it hits ground)

a= -9.81 m/s^2 t=???

Equation

the triangle means change in so d2-d1

Δd= v1 * t + 1/2 * a * t^2

0m-15m= v1*t + 1/2 a t^2

-15 m= 0m/s*t (goes away) + 1/2* a *t^2

-15mx2= t^2

-15mx2/a= t^2

Square root (-30/-9.81m/s^2)

t=1.75 s

b) now v2!!

Im going to use v2= v1 + a*t

v2= 0m/s + -9.81 x 1.75s

v2 = -17.2 m/s or you can say 17.2 m/s down!!!

7 0
2 years ago
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