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2 years ago

Label the places where you decide to measure current and voltage. Try several places

Physics

1 answer:

katen-ka-za [31]2 years ago

8 0

Answer:

Explore the Intro screen of Circuit Construction Kit DC

Build a circuit that shows how to make a light bulb light up.

Figure out how to measure current and voltage.

Insert an image of your circuit with the current and voltage measured.

Imagine you’re an engineer making a string of battery powered holiday lights. If a bulb burns out current cannot flow through that bulb any longer like if the wire at the bulb has been cut. Figure out how to hook up 2 light bulbs and a battery so that when one bulb burns out or is disconnected the other stays lit.

Insert images to illustrate that your circuit works as expected.

Explain why you think it works.

Imagine that you want to make sure the battery for your string of lights will last as long as possible. A battery will last longer if it powers a circuit with low current. How could you hook up a battery and 2 light bulbs so the least amount of current flows through the battery? Use the measurement tools in the simulation to check your design.

Insert images to illustrate that your circuit works as expected.

Explain why you think it works.

Develop your understanding Part 2

Instructions: Your goal in this part is to write rules to describe how patterns of current and voltage in a circuit relate to the structure of the circuit. You will need to measure current and voltage in multiple places on several different circuits.

Examples:

Measuring Current

Measuring Voltage

“Current” is the flow of charge, measured in Amps (Coulombs/s). An ammeter measures the current past a single point in the circuit.

The current flowing through point 1 can be written as:

I1 = 0.09 A.

“Voltage” is a measure of the difference in electric potential between two points. The voltmeter measures this difference by placing the two leads (pronounced “leeds”) at two different points.

The voltage between points A and B can be written as VAB = 9 V.

Explanation:

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. An object has a position given by ~r(t) = [3.0 m − (4.00 m/s)t]ˆı + [6.0 m − (8.00 m/s2 )t 2 ]ˆ , where all quantities are in

kupik [55]

Answer:

Explanation:

The position is $r(t) = [3.0 \text{ m} - (4.00 \text{ m/s})t]\hat{i} + [6.0 \text{m} - (8.00 \text{ m/s}^2 )t^2 ]\hat{j}$ .

The velocity is the first time-derivative of r(t).

$v(t) = \dfrac{d}{dt}r(t) = -4.00\,\hat{i} -16t\,\hat{j}$

The acceleration is the first time-derivative of the velocity.

$a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}$

Since a(t) does not have the variable t, it is constant. Hence, at any time,

$a = -16\hat{j}$

Its magnitude is 16 m/s².

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3 years ago

How much heat does it take to raise a cup of water (2.34 x 10-4 m3) from 15.0 °C to 75.0 °C?

Allisa [31]

Answer:58600

Explanation:

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2 years ago

A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge

Alexxx [7]

Explanation:

It is given that, a long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire.

The charge per unit length of the wire is $\lambda$ and the net charge per unit length is $2 \lambda$ .

We know that there exist zero electric field inside the metal cylinder.

(a) Using Gauss's law to find the charge per unit length on the inner and outer surfaces of the cylinder. Let $\lambda_i\ and\ \lambda_o$ are the charge per unit length on the inner and outer surfaces of the cylinder.