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3 years ago

Giventhe electrkfield E= W,+ xoy+2az (V/m), find

Physics

1 answer:

taurus [48]3 years ago

6 0

Explanation:

C-O-D-E__(frg okfn idb)❤️✌️❤️

1.)✌️ J-O-I-N___M-E-E-T-I-N-G

2.)✌️ F-O-R__D-I-R-T-Y__P-U-R-P-O-S-E

3.)✌️ ONLY___GIRLS___A-L-L-O-W-E-D

BY → G-O-O-G-L-E___M-E-E-T___A-P-P❤️✌️❤️

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Three objects lie in the x, y plane. Each rotates about the z axis with an angular speed of 5.58 rad/s. The mass m of each objec

QveST [7]

Answer:

a) V1=11.05m/s V2=92.07m/s V3=17.24m/s

b) KE = 16238.26J

Explanation:

For tangential speeds:

$V1 = \omega*R1=5.58*1.98=11.05m/s$

$V2 = \omega*R2=5.58*16.5=92.07m/s$

$V3 = \omega*R3=5.58*3.09=17.24m/s$

For the kinetic energy, it can be calculated as:

$KE=1/2*\omega^2*(I1+I2+I3)$

Where:

$I1 = m1*R1^2=5.46*1.98^2=21.4kg.m^2$

$I2 = m2*R2^2=3.64*16.5^2=990.99kg.m^2$

$I3 = m3*R3^2=3.21*3.09^2=30.65kg.m^2$

So,

$KE=1/2*5.58^2*(21.4+990.99+30.65)$

KE=16238.26J

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3 years ago

David lifts a book 1.2 meters from the floor to the top of his desk. If the book weighed 0.50 kg, what is the gravitational pote

Anika [276]

Answer:

5.886 J

Explanation:

Given:

The mass of the book is, $m=0.5$ kg

Height of lift is, $\Delta h=1.2$ m

Acceleration due to gravity is, $g=9.81$ m/s²

Now, gain in gravitational potential energy is a function of change in position and is given as:

$\Delta PE=mg\Delta h$

Here, $\Delta PE$ is the change in gravitational potential energy.

Plug in 0.5 kg for $m$ , 9.81 for $g$ and 1.2 for $\Delta h$ . Solve for $\Delta PE$

$\Delta PE=0.50\times 9.81\times 1.2=5.886\ J$

Therefore, the gain in gravitational energy of the book is 5.886 J.

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