Answer:
Explanation:
This problem is all about torque. The "rules" are that in order for a system to be in rotational equilibrium, the sum of the torques on the system have to equal 0 (in other words, they have to equal each other {cancel each other out}). The equation for torque is
τ = F⊥r where τ is torque, F⊥ is the perpendicular force, and r is the lever arm length in meters. We also have to understand that in general Forces moving clockwise are negative and Forces moving counterclockwise are positive. Now we're ready for the problem:
A. The counterclockwise torque:
τ = 300(3) so
τ = 900N*m
B. The clockwise torque:
τ = -450(2.5) so
τ = -1100N*m
C. Obviously the system is not in roational equilibrium because one side is experiencing a greater torque than the other. This system will move clockwise as it currently exists.
D. In order for the system to be in rotational equilibrium, we have to move Bob's location from the fulcrum. Let's see to where.
The torques have to be the same on both sides of the fulcrum; mathematically, that looks like this:
F⊥r = F⊥r Filling in:
300(3) = 450r and
900 = 450r so
2 = r. This means that Bob will have to move closer to the fulcrum by a half of a meter to 2 meters from the fulcrum in order for the system to be in balance.
Isn't this so much fun?!
The answer is A. a habitat’s features are determined by the abiotic factors such as temperature and humidity.
Your question has been heard loud and clear.
An alpha particle , can move in any direction randomly. But with a magnetic field , we can deflect the alpha particle in any direction we want.
So , the magnetic field must be placed to the west of the alpha particle , so that the particle gets deflected and moves towards the north direction.
Thank you.
Answer:
a) A = 0.603 m
, b) a = 165.8 m / s²
, c) F = 331.7 N
Explanation:
For this exercise we use the law of conservation of energy
Starting point before touching the spring
Em₀ = K = ½ m v²
End Point with fully compressed spring
= 
= ½ k x²
Emo =
½ m v² = ½ k x²
x = √(m / k) v
x = √ (2.00 / 550) 10.0
x = 0.603 m
This is the maximum compression corresponding to the range of motion
A = 0.603 m
b) Let's write Newton's second law at the point of maximum compression
F = m a
k x = ma
a = k / m x
a = 550 / 2.00 0.603
a = 165.8 m / s²
With direction to the right (positive)
c) The value of the elastic force, let's calculate
F = k x
F = 550 0.603
F = 331.65 N
I think it would be near the sun due.to high rays of sun
