Question

A car starts from rest and accelerates for 8.9 s with an acceleration of 3.8 m/s 2 . How far does it travel? Answer in units of m.

Answer 1

Answer:

150.5 m

Explanation:

The motion of the car is a uniformly accelerated motion, so we can use the following suvat equation to find the displacement:

$s=ut+\frac{1}{2}at^2$

where

s is the displacement

u is the initial velocity

t is the time

a is the acceleration

For the car in this problem,

u = 0

$a=3.8 m/s^2$

Substituting t = 8.9 s, we find the displacement of the car at that time:

$s=0+\frac{1}{2}(3.8)(8.9)^2=150.5 m$