Answer:
5.77% Error.
Explanation:
Given an experimental value of 275 g , and a theoretical value of 260 g, the percent error can be found using the equation:

% Error = ( | 260 - 275 | / 260 ) × 100 = ( | - 15 | / 260 ) × 100 = ( 15 / 260 ) × 100 = 1500/260 = 300 / 52 = 5.769230769230.. ≈ 5.77%
<span>Because you've added coefficients to the molecules on the right side of the equation, the number of oxygen atoms has changed. ...Add a coefficient of 5 to the oxygen molecule on the left side of the equation. ...<span>C3H8 + 5O2 --> 4H2O + 3CO2.</span><span>The carbon, hydrogen, and oxygen atoms are balanced</span></span>
We will assume complete dissociation.
Since we have the molarity of OH solution, we can calculate the p(OH) as follows:
p(OH) = -log(molarity of OH) = -log(<span>7.5×10-3) = 2.1249
It is known that: p(H) + p(OH) = 14
Therefore, p(H) can be calculated as follows:
p(H) = 14 - p(OH) = 14 - 2.1249 = 11.875</span>
2H₂ ₍g₎ + O₂ ₍g₎ --------> 2H₂O ₍l₎
If mass of water = 447 g
And mol =

then mol of H₂O =
= 24.83 mol
Mole ratio of H₂O : O₂ ≡ 2 : 1
Since mole of H₂O = 24.83 mol
then mole of O₂ = 24.83 mol ÷ 2
= 12.42 mol
Thus Mass of O₂ = 12.42 mol * (16 * 2) g / mol
= 397.28 g
Answer:
5 L
Explanation:
Molarity = mol/L ----> L = mol/molarity
2.0 moles / 0.4 M HF = 5 L