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sergejj [24]
3 years ago
5

in the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor, if you burn 50.0g of hydrogen a

nd produce 447g of water how much oxygen is reacted
Chemistry
1 answer:
Citrus2011 [14]3 years ago
6 0
2H₂ ₍g₎  +  O₂ ₍g₎  -------->  2H₂O ₍l₎

If mass of water =  447 g 
And mol =  \frac{MASS}{MOLAR  MASS}

then mol of H₂O  =  \frac{447 g}{((16)+(1 * 2) g / mol} 
                           =  24.83 mol

Mole ratio of  H₂O : O₂    ≡    2  :  1

Since mole of H₂O =  24.83 mol
then mole of O₂  =  24.83 mol  ÷  2
                           =  12.42 mol

Thus Mass of O₂  = 12.42 mol  *  (16 * 2) g / mol
                             = 397.28 g
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3 years ago
What is the oxidation state of each element in SO4(2–)?
nikklg [1K]

Answer:

The oxidation state of sulfur, S, is +6, and the oxidation state of oxygen, O, is - 2:

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Explanation:

Application of rules

1. <u>Ion SO₄²⁻</u>

In a neutral compound, the sum of the oxidation states of all the atoms that constitute the compound is equal to zero. In ions the sum of the oxidation states of the atoms is equal to the charge of the ion.

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<u>2. Oxygen</u>

With the exception of the peroxides, when oxygen is combined with other elements, it always has oxidation state - 2.

Hence, the total charge of the four atoms of oxygen in SO₄²⁻ is 4×(-2) = - 8.

<u>3. Sulfur</u>

Therefore, naming x the unknown oxidation state of S, you can set this equation:

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Conclusion

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3 years ago
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Answer:

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Explanation:

the self-sustaining fission reaction spread by neutrons which occurs in nuclear reactors and bombs.

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