<u>Answer:</u> The number of moles of
is 0.05 moles.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:

We are given:
Molarity of solution = 0.10 mol/L
Volume of solution = 1 L
Putting values in above equation, we get:

The chemical reaction for the ionization of sodium sulfate follows the equation:

By Stoichiometry of the reaction:
2 moles of sodium ions are produced by 1 mole of sodium sulfate
So, 0.10 moles of sodium ions will be produced by =
of sodium sulfate.
Hence, the number of moles of
is 0.05 moles.
Answer:
The effective nuclear charge (often symbolized as Zeff or Z*) is the net positive charge experienced by an electron in a multi-electron atom. The term “effective” is used because the shielding effect of negatively charged electrons prevents higher orbital electrons from experiencing the full nuclear charge.
Explanation:
Answer:
NH3 + CO2 + H2O -> NH4HCO3
This equation is already balanced
Answer:
Independent variables are ones that can be controlled and dependent variables are results of these changes. So, in question a, an independent variable is amount of a released energy, in these case in form of heat. We reduced that amount and as a result we get a dependent variable as high temperature of chocolate for longer time, so we changed time of a heat releasing from chocolate. In question b, an independent variable is temperature of water, and a dependent variable is amount of produced oxygen. In question c, an independent variable is an intensity of exercise. When we change the intensity of exercise, as a results, breathing rate is changed, which is dependent variable.
Explanation:
The mass of carbon dioxide will be 238.51g
<u>Explanation:</u>
Given:
Volume, V = 81.3 L
Pressure, P = 204 kPa
P = 204000Pa
Temperature, T = 95°C
T = 95 + 273K
T = 368K
mass of CO₂, m = ?
According to the gas law:
PV = nRT
where, R is the gas constant
n is the moles
and the value of R = 8.314 X 10³ L⋅Pa⋅K⁻¹⋅mol⁻¹
n = m/w
where,
m is the mass of the substance
w is the molecular weight
and molecular weight of CO₂ is 44 g
On substituting the value we get:

Therefore, the mass of carbon dioxide will be 238.51g