Evaluate the expression 40÷1+3-(3×7)+7-5

2 answers:

8 0

For this problem, you will have to use PEMDAS (Parentheses) (Exponents) (Multiplication/Division) (Addition/Subtraction)

First of all, you will want to solve for the values inside the parentheses first

40 <span>÷ 1+3-(21)+7-5 Now check for anything that includes multiplication/division and do that

40+3-21+7-5 All you have left now is addition and subtraction. It must go from left to right, therefore if addition is first, do addition, if subtraction is first, then do subtraction.

Final answer = 24</span>

Helga [31]3 years ago

7 0

You need to use PEDMAS for this.

40/1=3-(3 times 7) + 7-5

First the parenthesis.

(3 times 7 is 21 )

40/1+3-(21)+7-5

Next is exponents but there are none so move on to division.

40/1 = 40

40+3- (21) + 7-5

Then add and subtraction from left to right.

40+3=43

43- 21 + 7-5

43-21 is 22.

22+7-5

7-5 is 2

22+2 is 24

24 is the answer! :)

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