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ludmilkaskok [199]
3 years ago
10

How do you find the net force acting on an object?

Physics
1 answer:
weqwewe [10]3 years ago
4 0

Answer:

C. Add all the force vectors

Explanation:

The net force acting on an object is the vector sum of all the  forces on the object.

Remember, Newton's first law tells us a body at rest will remain at rest or that in uniform motion will continue in motion unless acted by unbalanced forces.These unbalanced forces act in all direction towards the body thus to get the net force you require a summation of all these force with respect to their magnitudes and directions.

For example a force of 3N towards the East direction acting on a body and another force of 2N towards the West direction on the same body will generate a net force of 1N towards the East direction.

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On December 26, 2004, a great earthquake occurred off the coast of Sumatra and triggered immense waves (tsunami) that killed som
k0ka [10]

Answers:

a) 222.22 m/s

b) 800.00 km/h

Explanation:

The speed of a wave is given by the following equation:

v=f \lambda

Where:

v is the speed

f=\frac{1}{T} is the frequency, which has an inverse relation with the period T=1 h

\lambda=800 km is the wavelength

Solving with the given units:

v=\frac{1}{T}\lambda

v=\frac{1}{1 h}800 km

v=800.00 km/h This is the speed of the wave in km/h

Transforming this speed to m/s:

v=800.00 \frac{km}{h} \frac{1 h}{3600 s} \frac{1000 m}{1 km}

v=222.22 m/s This is the speed of the wave in m/s

5 0
3 years ago
How do i calculate acceleration? pls help! thanks :)
LenKa [72]

The acceleration is 2 mph/min

Explanation:

The acceleration of an object is the rate of change of velocity. It is defined as follows:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time taken for the velocity to change from u to v

For the car in this problem, we have (taking North as positive direction):

u = 25 mph

v = 35 mph

t = 5 min

Substituting into the equation, we find the acceleration:

a=\frac{35 mph-25mph}{5min}=2 mph/min

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

4 0
3 years ago
Prisms seperate __ light, such as that from the Sun by wavelength
natka813 [3]

Answer: white

Explanation:

prisms separate white light, such as that from the sun by wavelength.

Brainliest

3 0
3 years ago
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0 °C for the following reacti
Yakvenalex [24]

The equilibrium constant of the reaction at 25⁰c will be 426827.5.

<u />

  • <u>Theory-</u>

<u>Equilibrium constant</u> :The equilibrium constant comes from the chemical equilibrium law. For the chemical equilibrium state, at a fixed constant temperature, the ratio of the product of the reaction's multiplication to the concentration of its reactants' multiplication, and each is raised to the power to the corresponding coefficients of the elements in the reaction.

The chemical equilibrium is given by for a general chemical reaction.

a. A+ b. B ⇌ c. C+ d. D,.

Kc =[C]c [D]d/[A]a [B]b.

<u>Gibb's free energy</u> :The second law of thermodynamics can be arranged in such a way that it gives a new expression when a chemical reaction happens at a constant temperature and constant pressure.

G=H-TS

  • <u>Calculations</u>:-

T=25⁰c

G=51.4 x 10³J

\\\\k=GR+\frac{nRT}{Z} \\

k= equilibrium constant ,G=Gibbs free energy ,n= no. of moles ,R=Gas constant ,T=temperature ,Z=compressibility

Ideal.Situation=\left \{ {{Z=1} \atop {n=1}} \right.

\\\\\\k=GR+RT

k=51.4 x 10³ x 8.3 + 8.3 x 25

k=426827.5

To learn equilibrium constant-

<u>brainly.com/question/19669218</u>

#SPJ4

6 0
1 year ago
Find the object's speeds v1, v2, and v3 at times t1=2.0s, t2=4.0s, and t3=13s.
zimovet [89]
The question is asking to calculate the object's speed v1, v2, v3 at the certain time is the given of the problem, in my calculation, I would say that the speed would be  2m/s, 1.5m/s, 0.22m/s. I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarification
7 0
3 years ago
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