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ludmilkaskok [199]

3 years ago

10

How do you find the net force acting on an object?

1 answer:

weqwewe [10]3 years ago

4 0

Answer:

C. Add all the force vectors

Explanation:

The net force acting on an object is the vector sum of all the forces on the object.

Remember, Newton's first law tells us a body at rest will remain at rest or that in uniform motion will continue in motion unless acted by unbalanced forces.These unbalanced forces act in all direction towards the body thus to get the net force you require a summation of all these force with respect to their magnitudes and directions.

For example a force of 3N towards the East direction acting on a body and another force of 2N towards the West direction on the same body will generate a net force of 1N towards the East direction.

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You are standing on a street corner with your friend. You then travel 14.0 m due west across the street and into your apartment

Margarita [4]

Answer:

Explanation:

We shall express each displacement vectorially , i for each unit displacement towards east , j for northward displacement and k for vertical displacement .

14 m due west = - 14 i

22.0 m upward in the elevator = 22 k

12 m north = 12 j

6.00 m east = 6 i

Total displacement = - 14 i + 22 k + 12 j + 6 i

D = - 8 i + 12 j + 22 k

magnitude = √ ( 8² + 12² + 22² )

= √ ( 64 + 144 + 484 )

= √ 692

= 26.3 m

Net displacement from starting point = 26.3 m .

5 0

2 years ago

How is distance related to force in this experiment to mass

Elden [556K]

When distance<span> is increased the amount of </span>force<span> needed will depend on the </span>mass<span> of the object. </span>

5 0

3 years ago

Two cylindrical resistors are made of the same material and have the same resistance. The resistors, R1 and R2, have different r

Paladinen [302]

Answer:

Option d is correct.

Explanation:

We know , resistance of a body is directly proportional to its length and inversely proportional to its area.

$R=\dfrac{\rho\ L}{A}=\dfrac{\rho\ L}{\pi r^2}$ ( Here, $\rho$ is constant dependent on object material )

Writing $R_1 \ and\ R_2$ also :

$R_1=\dfrac{\rho\ L_1}{\pi r_1^2}\ , \ R_2=\dfrac{\rho\ L_2}{\pi r_2^2}$ ( since they are of same material therefore, $\rho$ is same.)

Now , if $r_2=2r_1 \ and \ 4L_1=L_2$ .

Then $R_1=R_2$

Therefore, option d. is correct.

Hence, this is the required solution.

7 0

3 years ago

A scientist studying the Milky Way galaxy notices a bright light in the sky. What information would she need to prove that the o

Olin [163]

Answer:

Ist and second

Hope it helps

8 0

3 years ago

To stop a car, first you require a certain reaction time to begin braking; then the car slows under the constant braking deceler

ANEK [815]

Answer:

a) $t_r = 0.55 s$

b) a = 5.59 m/s²

Explanation:

given,

total distance traveled by the car to stop is 56.9 m when speed of vehicle is 80 km/h or 80 × 0.278 = 22.24 m/s

total distance traveled by the car to stop is 25.7 m when speed of vehicle is 50.7 km/h or 50.7 × 0.278 = 14.09 m/s

using stopping distance formula

$s_1 = v_1 t_r +\dfrac{v_1^2}{2 a}$ ................(1)

$s_2 = v_2 t_r +\dfrac{v_2^2}{2 a}$ ..............(2)

on solving both the equation we get

$a = \dfarc{v_1v_2(v_1-v_2)}{2(s_1v_2-s_2v_1)}$

$a = \dfarc{22.4\times 14.09(22.24-14.09)}{2(56.9\times 14.09-25.7\times 22.24)}$

a = 5.59 m/s²

now reaction time calculation

$t_r =\dfrac{v_1^2d_2-v_2^2d_1}{v_1v_2(v_1-v_2)}$

$t_r =\dfrac{22.24^2\times 25.7-14.09^2\times 56.9}{22.4\times 14.09(22.24-14.09)}$

$t_r = 0.55 s$

8 0

3 years ago