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ludmilkaskok [199]
3 years ago
10

How do you find the net force acting on an object?

Physics
1 answer:
weqwewe [10]3 years ago
4 0

Answer:

C. Add all the force vectors

Explanation:

The net force acting on an object is the vector sum of all the  forces on the object.

Remember, Newton's first law tells us a body at rest will remain at rest or that in uniform motion will continue in motion unless acted by unbalanced forces.These unbalanced forces act in all direction towards the body thus to get the net force you require a summation of all these force with respect to their magnitudes and directions.

For example a force of 3N towards the East direction acting on a body and another force of 2N towards the West direction on the same body will generate a net force of 1N towards the East direction.

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mote1985 [20]

Answer:

40479.6 J

Explanation:

Applying,

q = cm(t₂-t₁).................... Equation 1

Where q = change in heat content of the system, c = specific heat capacity of the system, m = mass of the system, t₁ = initial temperature, t₂ = final temperature.

From the question,

Given: m = 79 g = 0.079 kg, t₁ = 21°C, t₂ = 143°C

Constant: c = 4200 J/kg.°C

Substitute these values into equation 1

q = 4200(0.079)(143-21)

q = 331.8(122)

q = 40479.6 J

4 0
3 years ago
True or False?
WINSTONCH [101]

Answer:

true is the answer of the question

5 0
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Which evidence taken from a crime scene would be the best evidence for a District Attorney to gain a conviction with DNA evidenc
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Answer:

Blood

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6 0
3 years ago
A steel ball bearing is released from a height H and
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Answer:

ELASTIC collision

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As the ball bounces to the same height, it can be stated that the impact with the floor is ELASTIC.

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So the speed with which it descends is equal to the speed with which it rises

Therefore the kinetic energy of the ball before and after the collision is the same

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London lives 1200 meters south of Chick-fil-A and is thinking about going there for lunch. When she is ready to leave, she reali
saul85 [17]

Answer:

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  750 +1000 = 1750 . . . meters traveled

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