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viktelen [127]
3 years ago
5

Why are chemical changes considered “unseen”?

Physics
2 answers:
jeka57 [31]3 years ago
7 0
<span>Because they occur at an atomic level, changing the actual structure of the thing.

</span>
irinina [24]3 years ago
4 0
Chemical changes are usually considered unseen because it changes the chemical form of the atom, by breaking or forming new bonds.
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Two infinite plane sheets with uniform surface charge densities are placed parallel to each other with separation d. in the regi
kupik [55]

Answer:Uniform between the plates

Explanation:

Electric Field due to infinite sheet with uniform charge is given by

E=\dfrac{\sigma }{\epsilon _0}

Where \sigma=charge density

\epsilon _0=Space Permittivity

From the formula we can see that Electric field is independent of distance of the particle, so it is uniform between the plates .

3 0
3 years ago
How much work is done (in Joules) by a weightlifter in raising a 60-kg barbell from the floor to a height of 2m? Work done =
Vika [28.1K]

Answer:

1176 Nm or J

Explanation:

W = F*d

F = 60kg * 9.8 kgm/s^2 = 588 N

W = 588 N * 2m = 1176 N*m

7 0
3 years ago
Read 2 more answers
Convert 27,549 into scientific notation
dezoksy [38]
2.7549 x 10^4 is the answer I hope this helped u
7 0
3 years ago
An electroscope is a simple device consisting of a metal ball that is attached by a conductor to two thin leaves of metal foil p
baherus [9]

Answer:

the electroscope separate  by the presence of charge carriers

Explanation:

Metal bodies are characterized by having free (mobile) electrons. In the electroscope the plates are in balance; when the external metal ball is touched, a charge is introduced into the device, when the body that touched the ball is separated, an excess charge remains. This charge, being a metal, is distributed over the entire surface, giving a uniform density and an electric force of repulsion is created between the two charged sheets, which tends to separate the sheets. This force is counteracted by the tension component as the sheets are separated at a given angle, the separation reaches the point where

                  Fe - Tx = 0

                  Fe = Tx

In summary, the electroscope separate its leaves by the presence of charge carriers

3 0
3 years ago
A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calcu
galina1969 [7]

Question:

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

(a)60 (b)90 (c)120

Answer:

(a)5.42 N (b)6.26 N (c)5.42 N

Explanation:

From the question

Length of wire (L) = 2.80 m

Current in wire (I) = 5.20 A

Magnetic field (B) = 0.430 T

Angle are different in each part.

The magnetic force is given by

F=I \times B \times L \times sin(\theta)

So from data

F = 5.20 A \times 0.430 T \times 2.80 sin(\theta)\\\\F=6.2608 sin(\theta) N

Now sub parts

(a)

\theta=60^{o}\\\\Force = 6.2608 sin(60^{o}) N\\\\Force = 5.42 N

(b)

\theta=90^{o}\\\\Force = 6.2608 sin(90^{o}) N\\\\Force = 6.26 N

(c)

\theta=120^{o}\\\\Force = 6.2608 sin(120^{o}) N\\\\Force = 5.42 N

3 0
3 years ago
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