In any redox reaction, the substance that undergoes reduction will 3) <span> gain electrons and have a decrease in oxidation number.</span>
The two effects do impurities have on the melting point of an organic compound are given as ,
- They tend to lower the overall melting point of the compound versus the value for he pure material .
- They ends to increase the range of the melting point values .
The impurities decreases the melting point of the substance of organic compounds . This is because there are unwanted particles which weaken the lattice structure of the solids crystal due to which it become less stable and melts before its original melting point.
Example : Let take a clay and add dirt hen it breaks easily from the points where there is dirt . This is essentially what happens with impurities
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Answer:
Molarity of our solution= 0.46=0.5
Explanation:
When diluting a solution we can use the formula:
1
1
=
2
2
= M= Molarity of the solution
=V=volumes
On the left side, we'll put what we know/already have and on the right side of the formula we'll put down what we want to dilute it to.
Let's plug in what we already know.
(0.700M)(2L) = (M2)(3L)
Solve for M2 by dividing both sides by 3 so M2 will be by itself.
(0.700M)(2L)/(3L) = M2
M2= 0.46, we can round it up to 0.5
Answer:
C-14 => N-14 + β⁻
Explanation:
C-14 over time decays by beta emission to N-14. Before decay, C-14 nucleus contains 6 protons and 8 neutrons. It is accepted that a neutron (n°) is composed of 1 proton (p⁺) and 1 electron (e⁻). Beta emission indicates loss/discharge of a high energy e⁻ from the nucleus of C-14 leaving 7 protons and 7 neutrons. The number of protons defines the element, N-14 as a product of the decay process with the β particle (high energy electron) the other. To check, remember, the ∑mass Reactants = ∑mass Products (superscript numbers) and ∑reactant charges = ∑product charges (subscript numbers
₆C¹⁴ => ₇N¹⁴ + ₋₁e° or, C-14 => N-14 + β
Answer:
The element A is S (sulfur)
Explanation:
The elements for the 3erd period in the periodic table are Na, Mg, Al, Si, P, S, Cl and Ar.
The one that has 6 e⁻ in its valence shell is the S, because it is missing 2 e⁻ to reach the octet rule. 2 e⁻ to has the most stable noble gas conformation.
The IE of S = 3360 kJ/mol
It is a little lower than Cl because the electron is so far from the nucleus, that's why we have to apply a very low ionization energy to rip the electron off.