Explanation:
The given data is as follows.
Mass of ice dropped = 325 g
Initial temperature = 
= (30 + 273) K = 303 K
Final temperature = 
= (0 + 273) K = 273 K
Now, using density of water calculate the mass of ice as follows.
= 500 g
As the relation between heat energy, specific heat and change in temperature is as follows.
Q = 
= 
= 62750 J
Also, relation between heat energy and latent heat of fusion is as follows.
Q = m L
= 
= 108300 J
Therefore, we require 
heat but we have 40774.95 J.
So, 
= 
= 188.4 g
Hence, the mass of ice = 325 g - 188.4 g
= 137 g
Therefore, we can conclude that 137 g of ice will still be present when the contents of the pitcher reach a final temperature.
There are 67.6 ounces in a 2-liter soda.
The circulatory system and the respiratory system; The respiratory system takes in the oxygen which then goes into our bloodstream to help our cells convert it into ATP energy.
The required mole ratio of NH₃ to N₂ in the given chemical reaction is 2:4.
<h3>What is the stoichiometry?</h3>
Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.
Given chemical reaction is:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
From the stoichiometry of the reaction it is clear that:
4 moles of NH₃ = produces 2 moles of N₂
Mole ratio NH₃ to N₂ is 2:4.
Hence required mole ratio is 2:4.
To know more about mole ratio, visit the below link:
brainly.com/question/504601
for 39g water solute dissolved at 20C = solubility ( g/ 100 g H2O ) × mass of water = ( 11g / 100g H2O ) × 39g H2O = 4.29 g
amount of solute dissolved at 30 C =
= 23 / 100 * 39 = 8.97 g
Amount of extra solute dissolved = 8.97 - 4.29 = 4.7 g
