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Lera25 [3.4K]
2 years ago
14

How do we think that Mars lost atmospheric gas?

Chemistry
1 answer:
grin007 [14]2 years ago
7 0

the rocky planet was exposed to harsh and forceful solar winds, which blew the Martian atmosphere away.

Another option for thickening the atmosphere of Mars, and, in turn, raising the temperature of the planet, would be to set up solar-powered, greenhouse-gas producing factories.

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Given the balanced equation representing a reaction:
Vladimir79 [104]

Answer:

Option A. Addition

Explanation:

Unsaturated compounds under goes addition reaction to produce saturated compounds..

In the equation given above i.e

H2C=CH2 + F–F —> FCH2CH2F

we can see that the double in H2C=CH2 disappear by the reaction of F–F to produce FCH2CH2F which has no double. This simply indicates that the F–F was added to H2C=CH2. Hence, the reaction is called addition reaction.

4 0
3 years ago
Avery has a glass of pure water. She pours a tablespoon of sugar into the water to make it taste sweet.
SSSSS [86.1K]
The first blank is a compound, second is a mixture
8 0
3 years ago
I/3 of 12 = 2/3 of<br>please help at 11 o'clock am it needs to be done ​
Nostrana [21]

Answer:

6

Explanation:

This question is seeking for an equivalent of one expression. The first expression says 1/3 of 12, which means 1/3 × 12 = 4. To find 2/3 of a number that will give us 4, we say

Since; 1/3 of 12 is 4

Then, 4 = 2/3 of x, where x is the number, which when multiplied by two-third (2/3) will result to 4.

4 = 2/3 × x

4 = 2x/3

Cross multiply

2x = 3 × 4

2x = 12

x = 12/2

x = 6.

This means that; 1/3 of 12 = 2/3 of 6

4 0
3 years ago
The molecular mass of sodium oxide (Na2O) is
yuradex [85]
<span>The molecular mass of sodium oxide (Na2O) is A. 61.97894. The molecular mass of a molecule (Mr) is the sum of atomic masses of its atoms (Ar). The molecular mass of sodium oxide is: Mr(Na2O) = 2 * Ar (Na) + Ar(O). From the periodic table, Ar(Na) = 22.989769 and Ar(O) = 15.9994. The molecular mass of sodium oxide is: Mr(Na2O) = 2 * 22.989769 + 15.9994 = 45.979538 + 15.9994 = 61.97894.</span>
6 0
3 years ago
Suppose a grill lighter contains 50.0 g of butane. How many grams of butane in the lighter would have to be burned to produce 17
Hitman42 [59]

<span>Answer is: mass of burned butane is 11.6 g.</span>

Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.

m(butane) = 50,0 g.

<span> V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷ Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) : n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) = 0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) = 0,2 mol.<span>
m(C</span>₄H₁₀) = n(C₄H₁₀) · M(C₄H₁₀).<span>
m(C</span>₄H₁₀) = 0,2 mol · 58 g/mol.<span>
m(C</span>₄H₁₀) = 11,6 g.

5 0
3 years ago
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