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Pie
2 years ago
5

What is the atomic number and name of an element that has 15 protons in its nucleus?

Chemistry
2 answers:
TiliK225 [7]2 years ago
8 0

Answer:

The name is phosphorus and the number of atomic is 15

Explanation:

just olya [345]2 years ago
4 0

Answer:

phosphorus.

Explanation:

The atomic number of phosphorus is 15 so the protons will be 15.

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An atom with 4 protons and 4 neutrons Is called?
Bas_tet [7]

Answer:

i'm pretty sure it's beryllium

Explanation:

5 0
3 years ago
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Compute 4.659×104−2.14×104. Round the answer appropriately.
IrinaK [193]
<span>To compute 4.659×104−2.14×104, the first step is the factorization. That is as follows:4.659×104−2.14×104= 10^4.(4.659−2.14), the next step is to compute 4.659−2.14=2.51, so 10^4.(4.659−2.14)=2.51x10^4=2.51x 10000 (because10^4=10000), the last calculus is 2.51x 10000=25100, the final answer is 25,000.Hope this helps. Let me know if you need additional help!</span>
7 0
3 years ago
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Lead (II) nitrate reacts with ammonium carbonate to produce ammonium nitrate
vitfil [10]

Pb(NO₃)₂ + (NH₄)₂CO₃ → PbCO₃ + 2 NH₄NO₃

Explanation:

Reaction of lead (II) nitrate with ammonium carbonate will produce lead (II) carbonate and ammonium nitrate.

The balanced chemical equation is:

Pb(NO₃)₂ + (NH₄)₂CO₃ → PbCO₃ + 2 NH₄NO₃

To balance the chemical equation the number of atoms of each element   entering the reaction have to be equal to the number of atoms of each   element leaving the reaction, in order to conserve the mass.

Learn more about:

balancing chemical reactions

brainly.com/question/13911443

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3 0
3 years ago
I really need help with this chem question. Can anybody answer it with an explanation for the answer? Thanks.
4vir4ik [10]
C. Because you eliminate "spectator ions" or ions that are repeated and you can only do that to aqueous. So, Ca +2 and 2I -1 are the only ones you can remove for net ionic.
4 0
3 years ago
A sample of nitrogen gas expands in volume from 1.3 to 5.7 L at constant temperature. Calculate the work done in joules if the g
just olya [345]

Answer:

a) 0 J

b)  -2.67x10² J

c) -2.09x10³ J

Explanation:

For an isothermic expansion (with constant temperature) the work (W) is :

W = -pΔV, where p is the pressure and ΔV the volume variation. The minus signal is used because the compression is positive and ΔV is negative (Vf < Vi).

a) In vacuum, the relative pressure is 0 atm, so the work:

W = -0x(5.7 - 1.3)

W = 0 J

b) For a constant pressure of 0.60 atm

W = -0.6atmx(5.7 - 1.3)L = -2.64 L.atm

1 L.atm = 101.3 J

W = -2.64x101.3 = -2.67x10² J

c) For a pressure of 4.7 atm

W = -4.7atmx(5.7 - 1.3) L = - 20.68 atm.L

1 atm.L = 101.3 J

W = -20.68x101.3 = -2.09x10³ J

7 0
3 years ago
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