The answer is C because The products are way more stable than the reactants.
The limiting reagent : NH₃
<h3>Further explanation</h3>
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactants become a limiting reactant
Reaction
4NH₃(g)+5O₂(g)⇒4NO(g)+6H₂O(g)
mol NH₃ :
mol O₂ :
mol ratio
NH₃ :
O₂ :
Limiting reactants : NH₃ (smaller ratio)
Answer:First calculate the moles of selenium by multiplying the mass x molar mass 90.2 × 78.96 = 7122.2 moles. Number of moles multiplied by ...
Explanation:
Answer:
1-(tert-butoxy)-2-methylpropane
Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.
Explanation:
<em>Structural formula is attached</em>
IUPAC naming rules
1. start numbering the chain from the functional group. In this compound we start from oxygen side.
2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.
3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.
4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane
5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane