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motikmotik
3 years ago
13

The factor that is changed throughout an experiment is called the _______. A. apparatus B. constant C. variable D. hypothesis

Chemistry
2 answers:
yaroslaw [1]3 years ago
7 0

Answer:

C - Variable

Explanation:

Let’s see all the options in detail.

Apparatus: These are the equipment’s used in the experiment. Irrespective of the experiment result, the apparatus remains unchanged from start till the end.

Constant: These are factors that are fixed and does not change throughout the experiment.

Variable: A variable is any factor in an experiment that changes. As per dictionary, variable literally means something that varies i.e. change.  

Hypothesis: This is the underlying explanation in response to which the experiment is being conducted. Also, in an experiment, the hypothesis is not considered a factor at all.

<u>Therefore, the correct answer is </u><u>C. </u><u> </u>

ser-zykov [4K]3 years ago
4 0
The variable is what changes during an experiment. Hopefully this helped! :)
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Turmeric solution turns red in contact with bases and is not affected by acids and neutral substances. Put one drop of each liquid as the turmeric paper. The liquid whose drop turns the paper red is solution hydroxide (base).
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Molecular chlorine and molecular fluorine combine to form a gaseous product. Under the same conditions of temperature and pressu
uranmaximum [27]

Answer:

  • Cl F₃

Explanation:

<u>1) Reactants:</u>

The reactants are:

  • <em>Molecular chlorine</em>: this is a gas diatomic molecule, i.e. Cl₂ (g)

  • <em>Molecular fluorine</em>: this is also a gas diatomic molecule: F₂ (g)

<u>2) Stoichiometric coefficients:</u>

  • <em>One volume of Cl₂ react with three volumes of F₂</em> means that the reaction is represented with coefficients 1 for Cl₂ and 3 for F₂. So, the reactant side of the chemical equation is:

        Cl₂ (g) + 3F₂ (g) →

<u>3) Product:</u>

  • It is said that the reaction yields <em>two volumes of a gaseous product;</em> then, a mass balance indicates that the two volumes must contain 2 parts of Cl and 6 parts of F. So, one volume must contain 1 part of Cl and 3 parts of F. That is easy to see in the complete chemical equation:

       Cl₂ (g) + 3F₂ (g) → 2Cl F₃ (g)

        As you see, that last equation si balanced: 2 atoms of Cl and 6 atoms of F on each side, and you conclude that the formula of the product is ClF₃.

8 0
2 years ago
If ice is warmed and becomes a liquid, which type of process is it ?
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The answer is Endothermic

6 0
3 years ago
Read 2 more answers
Why does the high pressure air being released into the ballast tanks of a submarine cause it to rise quickly?
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Answer:

Initially, the ballast tanks are filled with water. The weight of the submarine is equal to the upthrust of the water at the position of the submarine under water. When high pressure air is released into the ballast tanks displacing the water, the weight of the submarine becomes less than  the upthrust of the water thus the net force is is upwards and it forces the sub to resurface. This is according to the Archimedes principle which states that a a body partially or wholly immersed in water displaces its own weight of the fluid in which it is immersed.

6 0
3 years ago
For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox
ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: m_{N2}=10.682 g N_2

2) Limiting reagent: NO

3) Ammount of excess reagent: m_{N2}=4.274 g

Explanation:

<u>The reaction </u>

2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)

Moles of nitrogen monoxide

Molecular weight: M_{NO}=30 g/mol

n_{NO}=\frac{m_{NO}}{M_{NO}}

n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol

Moles of hydrogen

Molecular weight: M_{H2}=2 g/mol

n_{H2}=\frac{m_{H2}}{M_{H2}}

n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted

m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}

m_{N2}=10.682 g N_2

2) <u>Limiting reagent</u>: NO

3) <u>Ammount of excess reagent</u>:

m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}

m_{N2}=4.274 g

8 0
3 years ago
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