Question

A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50-L container of cold water, what would be the approximate increase in the temperature of the water? ( Note: A liter of cold water weighs about 1 kg.)

Answer 1

Answer:

10°C  

Explanation:

Heat gain by water = Heat lost by the slice of pizza

Thus,    

$m_{water}\times C_{water}\times \Delta T=Q$

For water:  

Volume = 50.0 L

Density of water= 1 kg/L  

So, mass of the water:  

$Mass\ of\ water=Density \times {Volume\ of\ water}$  

$Mass\ of\ water=1 kg/L \times {50.0\ L}$  

Mass of water  = 50 kg

Specific heat of water = 1 kcal/kg°C  

ΔT = ?

For slice of pizza:  

Q = 500 kcal

So,

$50\times 1\times \Delta T=500$  

ΔT = 10°C  

Increase in temperature = 10°C