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zepelin [54]
3 years ago
10

Which of the following is a supersonic speed? Mach 0.005 Mach 0.05 Mach 0.5 Mach 5

Physics
2 answers:
Viktor [21]3 years ago
7 0
Mach 5. Mach 1 is defined as the speed of sound. The number after “Mach” is the multiplier. So Mach 5 is 5x the speed of sound.
vichka [17]3 years ago
5 0

I just had this question, the correct answer is March 5

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Astronomers determine that a certain square region in interstellar space has an area of approximately 2.4 \times 10^72.4×10 ​7 ​
mafiozo [28]

Answer:

1.5 × 10³⁶ light-years

Explanation:

A certain square region in interstellar space has an area of approximately 2.4 × 10⁷² ​​ (light-years)². The area of a square can be calculated using the following expression.

A = l²

where,

A is the area of the square

l is the side of the square

l = √A = √2.4 × 10⁷² ​​ (light-years)² = 1.5 × 10³⁶ light-years

5 0
3 years ago
You want to calculate the density of a marble what is one piece of data that you need A the weight B the volume C how fast the m
8090 [49]
C I think but I’m not really sure....
4 0
2 years ago
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A car possesses 20,000 units of momentum. what would be the car's new momentum if ... its velocity was doubled?
pochemuha
10,000 units of momentum.
p=mv
20,000=m(2v)
10,000=mv
7 0
3 years ago
Two sound waves are traveling through the same medium. They have the same amplitude, wavelength, and direction of travel. If the
Sloan [31]

Answer:

Constructive interference

Explanation:

Here, the medium is same, same wavelength, same frequency, same amplitude and same direction of propagation.

Let the intensity of waves be I which is same for both

The formula for the net intensity is

I^{2}=I_{1}^{2}+I_{2}^{2}+2I_{1}I_{2}Cos\phi

where, Ф be the phase difference

So, I_{R}^{2}=I^{2}+I^{2}+2IICos6\pi

Here, IR is maximum so the interference is constructive in nature.

7 0
3 years ago
A parallel beam of light in air makes an angle of 43.5 ∘ with the surface of a glass plate having a refractive index of 1.68. Yo
aniked [119]

Answer:

a) 46.5º  b) 64.4º

Explanation:

To solve this problem we will use the laws of geometric optics

a) For this part we will use the law of reflection that states that the reflected and incident angle are equal

     θ = 43.5º

This angle measured from the surface is

     θ_r = 90 -43.5

     θ_s = 46.5º

b) In this part the law of refraction must be used

     n₁ sin θ₁ = n₂. Sin θ₂

     sin θ₂ = n₁ / n₂ sin θ₁

The index of air refraction is n₁ = 1

The angle is this equation is measured between the vertical line called normal, if the angles are measured with respect to the surface

     θ_s = 90 - θ

     θ_s = 90- 43.5

     θ_s = 46.5º

     sin θ₂ = 1 / 1.68  sin 46.5

     sin θ₂ = 0.4318

     θ₂ = 25.6º

The angle with respect to the surface is

     θ₂_s = 90 - 25.6

     θ₂_s = 64.4º

measured in the fourth quadrant

3 0
2 years ago
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