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3 years ago

Which of the following is a supersonic speed? Mach 0.005 Mach 0.05 Mach 0.5 Mach 5

2 answers:

7 0

Mach 5. Mach 1 is defined as the speed of sound. The number after “Mach” is the multiplier. So Mach 5 is 5x the speed of sound.

vichka [17]3 years ago

5 0

I just had this question, the correct answer is March 5

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Science: Physics AND Biology - Please help me with these, it's due tonight.

Ostrovityanka [42]

The answer to the first question is that plants make glucose and oxygen by taking in CO2 and H20.

The answer to the second question is having a heavier mass increases the force of a moving object. That is the Second Law of Motion, F = ma.

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3 years ago

Sally is concerned about the X-ray images her dentist plans to take of her teeth. She has read that X-rays can cause tissue effe

taurus [48]

Answer:

The dentist uses X-ray radiography, which takes too short a time to cause those problems.

Explanation:

I took the test on Edg

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3 years ago

Which type of mountain forms because of two oceanic plates colliding?

Snowcat [4.5K]

<span>''Aelutian'' is the type of mountain that forms.</span>

8 0

2 years ago

Read 2 more answers

A mover applies a net force of 28 N to a sofa that has a mass of 70 kg.

Alinara [238K]

Answer: .4 m/s^2= acceleration

Explanation:

f = m*a

We can rearrange this equation to solve for acceleration. Therefore,

a=f/m

a= 28N/70kg

a= 0.4 m/s^2

8 0

3 years ago

An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char

ArbitrLikvidat [17]

Answer:

Part a)

$W = 1.58 \times 10^{-20} J$

Part b)

$v = 1.86 \times 10^5 m/s$

Explanation:

Part a)

Electric field due to large sheet is given as

$E = \frac{\sigma}{2\epsilon_0}$

$\sigma = 4.00 \times 10^{-12} C/m^2$

now the electric field is given as

$E = \frac{4.00 \times 10^{-12}}{2(8.85 \times 10^{-12})}$

$E = 0.225 N/C$

Now acceleration of an electron due to this electric field is given as

$a = \frac{eE}{m}$

$a = \frac{(1.6 \times 10^{-19})(0.225)}{9.1 \times 10^{-31}}$

$a = 3.97 \times 10^{10}$

Now work done on the electron due to this electric field

$W = F.d$

$d = 0.470 - 0.03$

$d = 0.44 m$

So work done is given as

$W = (ma)(0.44)$

$W = (9.11 \times 10^{-31})(3.97 \times 10^{10})(0.44)$

$W = 1.58 \times 10^{-20} J$

Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

so we will have

$W = \frac{1}{2}mv^2 - 0$

$1.58 \times 10^{-20} = \frac{1}{2}(9.1\times 10^{-31})v^2$

$v = 1.86 \times 10^5 m/s$

7 0

2 years ago