3. A force of 200 N is applied to an object of area 2 sq.m . the pressure will be
2 answers:
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Explanation:
It is given that,
Mass of the ball, m = 0.06 kg
Initial speed of the ball, u = 50.4 m/s
Final speed of the ball, v = -37 m/s (As it returns)
(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :
J = -5.24 kg-m/s
(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.
W = -35.1348 Joules
Hence, this is the required solution.
The angular speed is decreasing and direction of rotation clockwise of the rod immediately after time t.
<h3></h3><h3>What is angular speed ?</h3>The rate of change of angular displacement is defined as angular speed. It is stated as follows:
ω = θ t
Where,
θ is the angle of rotation,
t is the time
ω is the angular velocity
The torque is found as;l
If the force is acting on the rod from the three point is the same, the value of the torque is depends upon the radius or the perpendicular distance.
The perpendicular distance of the right force is grater. Hence, the force acting on the right side is more, and the rod will rotate clockwise.
Both the forces are acting downwards. Thus, the resultant force is the less due to which the speed is increasing.
Hence, the angular speed is decreasing and direction of rotation clockwise of the rod immediately after time t.
To learn more about the angular speed, refer to the link;
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Answer: Their final relative velocity is -0.412 m/s.
Explanation:
According to the law of conservation,
Putting the given values into the above formula as follows.
v =
= -0.412 m/s
Thus, we can conclude that their final relative velocity is -0.412 m/s.