The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²
<h3>Circular motion</h3>
From the question, we are to determine the magnitude of the centripetal acceleration.
Centripetal acceleration can be calculated by using the formula

Where
is the centripetal acceleration
is the velocity
and
is the radius
From the given information

and 
Therefore,



Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²
Learn more on circular motion here: brainly.com/question/20905151
It's pretty simple. When air is leaking out of a tire, like a tiny hole or something, the pressure in the tire decreases, because without air in the tire, there is no pressure.
Answer:
B. Direction
Explanation:
Speed is a scalar quantity and doesn't keep track of direction : Velocity is a vector quantity and is direction aware.
Answer:
<h3>1/16</h3>
Explanation:
According to the coulombs law, the force existing vetween the ions is expressed as;
F = kQq/r² .... 1
Q and q are the ions
r is the distance between the ions
If the distance between the ion is quadrupled, then;
F2 = kQq/(4r)²
F2 = kQq/16r² ... 2
Divide equation 2 by 1;
F2/F = kQq/16r² ÷ kQq/r²
F2/F = kQq/16r² × r²/kQq
F2/F = 1/16
F2 = 1/16 F
Therefore the coulombic force between two ions is reduced to<u> 1/16 </u>of its original strength when the distance between them is quadrupled.