Let the left end A and the right end B.
Let w = the weight of the full beam.
0 = -(w/2)*(L/4) - (w)*(L/2) + Fa*L
Fa = [(w/2)*(L/4) + (w)*(L/2)]/L = w/8 + w/2 = 5/8*w = 5/8*m*g = 5/8*1800*9.81 Fa = 11036.25 N
Fa + Fb = w Fb = w - Fa = 1.8*(1800*9.81) - 11036.25 Fb = 20748.15 N
Explanation:
the weight of an object is its force exerted by gravity.
on earth we take gravitational acceleration to be 9.8 m/s^2
so the weight of an object on earth is given by F = mg
hence,
F = 90 × 9.8
F = 882 Newtons (weight on earth)
gravitational acceleration on the moon is equal to 9.8/6. so, we can just use the same formula to find the weight on the moon.
F = 90 × 9.8/6
F = 147 Newtons (weight on the moon)
make sure to ask if you need any further guidance.
<span>Remember that impulse = change in
momentum
this means we compute the momentum of the ball just before impression and just
after; we know the mass, so we find the speeds
the ball falls for 1.5m and will achieve a speed given by energy
conservation:
1/2 mv^2 = mgh => v=sqrt[2gh]=5.42m/s
since it rises only to 0.85 m, we compute the initial speed after power from
the same equation and get
v(after)=sqrt[2*9.81m/s/s*0.85m] = 4.0837 m...
now, recall that momentum is a vector, so that the momentum down has one sign and
the momentum up has a positive sign, so we have
impulse = delta (mv) = m delta v = 0.014 kx (4.08m/s - (-5.42m/s) = 0.133 kgm/s </span>
Answer: A Answers. Assuming that the terminal velocity doesn't change during the fall, then the kinetic energy would remain constant. However the terminal velocity decreases during the fall since the air becomes denser at lower altitudes.
Explanation:
What happens to the KE of an object when it slows down and heats up? - Quora. The kinetic energy goes down and the loss of the kinetic energy is through the production of heat energy. In real world this is due to friction, or an opposing force that decelerates the object, or a combination of both.
An electron has a negative charge. Hope this helps.
