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Sedbober [7]
3 years ago
6

If the distance between two objects decreased, what would happen to the force of gravity between them?

Physics
2 answers:
evablogger [386]3 years ago
6 0

Answer: A- It would increase

Explanation:

According to the law of universal gravitation:

F=G\frac{m_{1}m_{2}}{r^2}  

Where:  

F is the module of the attraction force exerted between both objects

G is the universal gravitation constant.  

m_{1} and m_{2} are the masses of both objects  

r is the distance between both objects

As we can see, the gravity force is directly proportional to the mass of the bodies or objects and inversely proportional to the square of the distance that separates them.

In other words:

<h2>If we decrease the distance between both objects, the gravitational force between them will increase.  </h2>
boyakko [2]3 years ago
5 0

Answer:

it would stay the same

Explanation: i just took the quiz

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What is the objective lens?
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The objective lens is an optical tool used to focus an image.

Explanation:

The objective lens is an optical tool that collects light emitted by an object under observation and focuses the  rays of light in order to form a real and magnified image  They are used in optical instruments like microscopes, cameras, telescopes, etc. and are also referred as objective or object glasses.

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When monochromatic light shines perpendicularly on a soap film (n = 1.33) with air on each side, the second smallest nonzero fil
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Let us start from considering monochromatic light as an incidence on the film of a thickness t whose material has an index of refraction n determined by their respective properties.

From this point of view part of the light will be reflated and the other will be transmitted to the thin film. That additional distance traveled by the ray that was reflected from the bottom will be twice the thickness of the thin film at the point where the light strikes. Therefore, this relation of phase differences and additional distance can be expressed mathematically as

2t + \frac{1}{2} \lambda_{film} = (m+\frac{1}{2})\lambda_{film}

We are given the second smallest nonzero thickness at which destructive interference occurs.

This corresponds to, m = 2, therefore

2t = 2\lambda_{film}

t = \lambda_{film}

The index of refraction of soap is given, then

\lambda_{film} = \frac{\lambda_{vacuum}}{n}

Combining the results of all steps we get

t = \frac{\lambda_{vacuum}}{n}

Rearranging, we find

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4 0
3 years ago
What is the name for the bunched up region of<br> air particles in the sound wave?
Leviafan [203]

Answer:

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Explanation:

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