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klasskru [66]
4 years ago
14

Jasmine needs 22 yards of material

Mathematics
1 answer:
garri49 [273]4 years ago
3 0

Jasmine needs 20.02 meters to make the drapes

Step-by-step explanation:

Jasmine needs 22 yards of material  to make drapes, but the fabric

store sells material by the meter, we need to find how many meters

of material Jasmine needs to make the drapes

  • If 1 yard equals about 0.91 meters
  • Change 22 yards to meters

∵ 1 yard = 0.91 meters

∵ To make the drapes she needs 22 yards

- Use the ratio method

→  Yard    :    Meter

→  1           :   0.91

→  22        :   x

- By using cross multiplication

∴ 1(x) = 0.91(22)

∴ x = 20.02 meters

Jasmine needs 20.02 meters to make the drapes

Learn more:

You can learn more about word problems in brainly.com/question/10557275

#LearnwithBrainly

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Answer:

The simplest form of  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}  is  \frac{2}{(x+1)(x+3)}

Step-by-step explanation:

To add two algebraic fractions do these steps

  1. Factorize each denominator
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To simplify \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}

Factorize each denominator

∵ The denominator of the first fraction is x² + 5x + 6

∵ x² = (x)(x)

∵ 6 = (2)(3)

∵ (2)(x) + (3)(x) = 5x ⇒ middle term

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∵ x² = (x)(x)

∵ 2 = (2)(1)

∵ (2)(x) + (1)(x) = 3x ⇒ middle term

∴ x² + 3x + 2 = (x + 2)(x + 1)

Find the LCM of the two denominators

∵ The denominators are (x + 2)(x + 3) and (x + 2)(x + 1)

- LCM is all the <u><em>different factors</em></u> multiplied together

∴ LCM of them is (x + 1)(x + 2)(x + 3)

- Divide LCM by each denominator

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 3) = (x + 1)

- Multiply the numerator of the first fraction by (x + 1)

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 1) = (x + 3)

- Multiply the numerator of the second fraction by (x + 3)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{x+1}{(x+1)(x+2)(x+3)}+\frac{x+3}{(x+1)(x+2)(x+3)}

- Add the numerators and write the answer as a single fraction

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2x+4}{(x+1)(x+2)(x+3)}

- Factorize the numerator by taking 2 as a common factor

∵ 2x + 4 = 2(x + 2)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2(x+2)}{(x+1)(x+2)(x+3)}

- Simplify the fraction by dividing up and down by (x + 2)

∴  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2} = \frac{2}{(x+1)(x+3)}

The simplest form of  \frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}  is  \frac{2}{(x+1)(x+3)}

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