We know from physics class that the formula for distance of
a linear motion is given as:
d = v t
Where,
d = distance travelled
v = average velocity
t = time it took to reach the destination
Since the distance going to the office and back is just
similar, therefore we can simply equate the two:
v1 t1 = v2 t2
Where 1 signifies going to the office and 2 signifies going
back from the office. Therefore this yields to:
v1 * 5 hours = 65 mph * 4 hours
v1 = 52 mph
<span>Answer: The average
speed going to the office is 52 mph.</span>
Step-by-step explanation:
A rigid transnformation is also know as isometrie. <u>This are transformations of the plane that preserves the lengths</u>. There are 3 types of isometries and each one can be combined with the others.
- Reflection (First figure)
- Translation (second figure)
- Rotation (third figure)
Combining this transformations you will be able to transform ΔJKL onto ΔPQR
7 10 thousands is equal to 70 thousand
Answer:
624.5 feet
Step-by-step explanation:
Calculation to determine how many feet from the boat is the parasailor
Based on the information given we would make use of Pythagorean theorem to determine how many feet from the boat is the parasailor using this formula
a²+b²=c²
First step is to plug in the formula by substituting the given value
500²+b²=800²
Second step is to evaluate the exponent
250,000+b²=640,000
Third step is to substract 250,000 from both side and simplify
250,000+b²-250,000=640,000-250,000
b²=390,000
Now let determine how many feet from the boat is the parasailor
Parasailor feet=√b²
Parasailor feet=√390,000
Parasailor feet=b=624.49
Parasailor feet=b=624.5 feet (Approximately)
Therefore how many feet from the boat is the parasailor will be 624.5 feet
