The answer is
<em>All the three light bulbs will glow</em>
hope this helps
To solve this problem we will apply the concepts related to centripetal acceleration, which will be the same - by balance - to the force of gravity on the body. To find this acceleration we must first find the orbital velocity through the Doppler formulas for the given periodic signals. In this way:
![v_{o} = c (\frac{\lambda_{max}-\bar{\lambda}}{\bar{\lambda}}})](https://tex.z-dn.net/?f=v_%7Bo%7D%20%3D%20c%20%28%5Cfrac%7B%5Clambda_%7Bmax%7D-%5Cbar%7B%5Clambda%7D%7D%7B%5Cbar%7B%5Clambda%7D%7D%7D%29)
Here,
Orbital Velocity
Maximal Wavelength
Average Wavelength
c = Speed of light
Replacing with our values we have that,
![v_{o} = (3*10^5) (\frac{3.00036-3}{3})](https://tex.z-dn.net/?f=v_%7Bo%7D%20%3D%20%283%2A10%5E5%29%20%28%5Cfrac%7B3.00036-3%7D%7B3%7D%29)
<em>Note that the average signal is 3.000000m</em>
![v_o = 36 km/s](https://tex.z-dn.net/?f=v_o%20%3D%2036%20km%2Fs)
Now using the definition about centripetal acceleration we have,
![a_c = \frac{v^2}{r}](https://tex.z-dn.net/?f=a_c%20%3D%20%5Cfrac%7Bv%5E2%7D%7Br%7D)
Here,
v = Orbit Velocity
r = Radius of Orbit
Replacing with our values,
![a = \frac{(36km/s)^2}{100000km}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%2836km%2Fs%29%5E2%7D%7B100000km%7D)
![a= 0.01296km/s^2](https://tex.z-dn.net/?f=a%3D%200.01296km%2Fs%5E2)
![a = 12.96m/s^2](https://tex.z-dn.net/?f=a%20%3D%2012.96m%2Fs%5E2)
Applying Newton's equation for acceleration due to gravity,
![a =\frac{GM}{r^2}](https://tex.z-dn.net/?f=a%20%3D%5Cfrac%7BGM%7D%7Br%5E2%7D)
Here,
G = Universal gravitational constant
M = Mass of the planet
r = Orbit
The acceleration due to gravity is the same as the previous centripetal acceleration by equilibrium, then rearranging to find the mass we have,
![M = \frac{ar^2}{G}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7Bar%5E2%7D%7BG%7D)
![M = \frac{(12.96)(100000000)^2}{ 6.67*10^{-11}}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B%2812.96%29%28100000000%29%5E2%7D%7B%206.67%2A10%5E%7B-11%7D%7D)
![M = 1.943028*10^{27}kg](https://tex.z-dn.net/?f=M%20%3D%201.943028%2A10%5E%7B27%7Dkg)
Therefore the mass of the planet is ![1.943028*10^{27}kg](https://tex.z-dn.net/?f=1.943028%2A10%5E%7B27%7Dkg)
×top and bottom by 2
(you don't have to but it is easier)
6/14=3/7
weight of 30 Kg object= 300 N
Explanation:
Weight= m I
m= mass=30 kg
I= gravitational filed strength= 10 N/kg
weight=30 (10)
weight=300 N
Answer: Crustal Accretion or Crustal Generation
Explanation: These are the terms used to describe the process of new crust formation.