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blondinia [14]
3 years ago
13

Rays of light strike a bumpy road and are reflected.

Physics
2 answers:
Masteriza [31]3 years ago
8 0

Answer:

D. Each will reflect at an angle equal to its angle of incidence.

Explanation:

ser-zykov [4K]3 years ago
6 0

Answer:

last option is the correct one

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If you tried to use a diverging lens as a magnifier by placing the object at the focal point, what type of image would be produc
gladu [14]

Answer:

Upright and smaller than the object

Explanation:

Diverging lens as the name suggests that the rays diverge after the refraction and do not meet in reality. A concave lens is called diverging lens. When there is refraction of light through a concave lens then the light bends away from the principal axis and hence never meet in reality but on tracing the rays backwards the rays appear to meet leading to the formation of a virtual image, which is erect and smaller than the object for an object placed at the focus of the lens.

Similar image is formed for any case when the object is between optical center and infinity.

7 0
4 years ago
What are the characteristics of low energy waves
Degger [83]
Some characteristics I think would include that low energy waves have a greater distance between the points on the crest or points on trough in the wave. Greater, longer wavelength. Thus lower frequency hence less energy provided through the wave. The amplitude for low energy waves is less than that of high energy waves. Basically the height of the wave.
3 0
3 years ago
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¿Qué es una onda electromagnética?
Leya [2.2K]

Answer:

Son aquellas ondas que no necesitan un medio material para propagarse. Incluyen, entre otras, la luz visible y las ondas de radio, televisión y telefonía. Todas se propagan en el vacío a una velocidad constante, muy alta (300 0000 km/s) pero no infinita.

3 0
3 years ago
Two wires, both with current out of the page, are next to one another. The wire on the left has a current of 1 A and the wire on
Soloha48 [4]

Answer:

C. The left wire attracts the right wire and exerts as much force as the right wire does.

Explanation:

To know what is the answer you first take into account the magnetic field generated by each current, for a distance of d:

B_1=\frac{\mu_oI_1}{2\pi d}=\frac{\mu_o}{2\pi d}(1A)\\\\B_2=\frac{\mu_oI_2}{2\pi d}=\frac{\mu_o}{2\pi d}(2A)=2B_1\\\\

Next, you use the formula for the magnetic force produced by the wires:

\vec{F_B}=I\vec{L}\ X \vec{B}

if the direction of the L vector is in +k direction, the first wire produced a magnetic field with direction +y, that is, +j and the second wire produced magnetic field with direction -y, that is, -j (this because the direction of the magnetic field is obtained by suing the right hand rule). Hence, the direction of the magnetic force on each wire, produced by the other one is:

\vec{F_{B1}}=I_1L\hat{k}\ X\ B_2(-\hat{j})=I_1LB_2\hat{i}=(2A^2)\frac{L\mu_o}{2\pi d}\hat{i}\\\\\vec{F_{B2}}=I_2L\hat{k}\ X\ B_2(\hat{j})=I_2LB_1\hat{i}=-(2A^2)\frac{L\mu_o}{2\pi d}\hat{i}

Hence, due to this result you have that:

C. The left wire attracts the right wire and exerts as much force as the right wire does.

6 0
4 years ago
Which of the following bounces light in another direction?
Natali [406]

Answer:

I do believe the answer is D. prism

3 0
3 years ago
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