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bogdanovich [222]
3 years ago
13

Please help me with these questions

Chemistry
2 answers:
Otrada [13]3 years ago
7 0
Water helps your food go inside your body instead of staying in your throat
Gnesinka [82]3 years ago
4 0
1) Agricultural purposes
2) Cooking
3) Cleaning
4) Industrial purposes
5) Boating
6) Swimming
7) Travel purposes
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How is mass calculated given density and volume? (1 point) Question 8 options: 1) Volume divided by volume 2) Sum of volume and
laila [671]

Answer:

3) Density multiplied by volume

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

So by rearranging this formula mass can be determine.

 d = m/v

m = d×/v

Unit of mass when volume in mL and ddensity is g/mL

m = g/mL×mL

m = g

Example:

density = 5g/mL

volume = 3 mL

mass = ?

m = d×v

m = 5g/mL ×3 mL

m = 15 g

8 0
3 years ago
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How does water affect the melting temperature of rock?
Debora [2.8K]
Heat is the most important thing in the melting point of rock. Rock, melts when put into<span> 572 degrees Fahrenheit and 1,292 degrees Fahrenheit. Different types of rock may melt at different temperature because in the difference of their material. HOPED THIS HELPS YOU :)</span>
4 0
3 years ago
In the reaction 2co ( g) + o2( g) → 2co2( g), what is the ratio of moles of oxygen used to moles of co2produced?
KIM [24]
In the reaction 2co ( g) + o2( g) → 2co2( g), the ratio of moles of oxygen used to moles of co2produced is 1:2.
8 0
3 years ago
a flask was filled with SO2 at a partial pressure of 0.409 atm and O2 at a partial pressure of 0.601 atm. The following gas-phas
jarptica [38.1K]

Answer:

The equilibrium partial pressure of O2 is 0.545 atm

Explanation:

Step 1: Data given

Partial pressure of SO2 = 0.409 atm

Partial pressure of O2 = 0.601 atm

At equilibrium, the partial pressure of SO2 was 0.297 atm.

Step 2: The balanced equation

2SO2 + O2 ⇆ 2SO3

Step 3: The initial pressure

pSO2 = 0.409 atm

pO2 = 0.601 atm

pSO3 = 0 atm

Step 4: Calculate the pressure at the equilibrium

pSO2 = 0.409 - 2X atm

pO2 = 0.601 - X atm

pSO3 = 2X

pSO2 = 0.409 - 2X atm = 0.297

 X = 0.056 atm

pO2 = 0.601 - 0.056 = 0.545 atm

pSO3 = 2*0.056 = 0.112 atm

Step 5: Calculate Kp

Kp = (pSO3)²/((pO2)*(pSO2)²)

Kp = (0.112²) / (0.545 * 0.297²)

Kp = 0.261

The equilibrium partial pressure of O2 is 0.545 atm

3 0
3 years ago
Cells contain parts known as organelles these parts are specialized. What does this mean?
Eddi Din [679]

Answer:

because they devlop our organs

7 0
2 years ago
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