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il63 [147K]
2 years ago
10

If there are 3 moles of hydrogen, 6 moles of oxygen, and 9 moles of helium in a 10 L vessel at 27°C, the total pressure of the g

as
mixture will be:
A. 55 atm
B.
105 atm
C.
18 atm
D. 44 atm
Reset
Submit
Chemistry
1 answer:
harkovskaia [24]2 years ago
4 0

Answer:

The correct answer is D) 44 atm

Explanation:

We apply Dalton's law, where for a gas mixture the total pressure is the sum of the partial pressures of each gas that makes up that mixture. You can add the amount of moles and then calculate the pressure, using the ideal gas formula. We convert the temperature in Celsiud into Kelvin : 0°C= 273K---->

27°C=27 + 273= 300K

PV= (nH+ n0+ nHe)x RT

P=((nH+ n0+ nHe)x RT)/V=

P=((3 mol + 6 mol +9 mol)x 0,082 l atm/ Kmol x300K)/10 L

<em>P=44, 28 atm</em>

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The question is incomplete, the complete question is:

Nitrogen and fluorine react to form nitrogen fluoride according to the chemical equation:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

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<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

In the given chemical reaction, N_2 is considered as a limiting reagent because it limits the formation of the product and it was completely consumed in the reaction.

We are given:

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