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cricket20 [7]
3 years ago
12

Consider the molecules: scl2, f2, cs2, cf4, and brcl. select the choice where the bonds of the molecules are arranged in order o

f increasing polarity.
Chemistry
1 answer:
elena-s [515]3 years ago
5 0

The polarity of a bond depends on the difference in electronegativities of the atoms involved in bonding. Greater this difference, greater is the polarity

1) In SCl2 we have the S-Cl bond

Electronegativity values: S = 2.5, Cl = 3

Difference = 3.0 -2.5 = 0.5

2) In F2 we have the F-F bond

Electronegativity value: F = 4.0

Difference = 4.0-4.0 = 0

3) In CS2 we have the C-S bond

Electronegativity value: C = 2.5, S = 2.5

Difference = 2.5 -2.5 = 0

4) In CF4 we have the C-F bond

Electronegativity values: C = 2.5, F = 4.0

Difference = 4.0 -2.5 = 1.5

5) In BrCl we have the Br-Cl bond

Electronegativity values: Br = 2.8, Cl = 3

Difference = 3.0 -2.8 = 0.2

Therefore, the increasing order of polarity is

F2 = CS2 < BrCl < SCl2 < CF4

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Aleks04 [339]

Given :

pH of solution of mixture of lactic acid and lactate is 4.26 .

To Find : log( \dfrac{[ \text{Conc. of lactate}]}{[\text{Conc . of lactic acid }]})  = 0.4

The ratio of the lactate concentration to the lactate .

Solution :

We know , pKa of lactic acid is :

pKa = 3.86 .

Now , the solution of lactic acid and lactate is a buffer solution .

So , pHof buffer acid is given by :

pH=pKa+log(\dfrac{[Salt]}{[Acid]})

Putting all given values :

log( \dfrac{[ \text{Conc. of lactate}]}{[\text{Conc . of lactic acid }]})  = 0.4

Taking anti log both the sides , we get :

\dfrac{[ \text{Conc. of lactate}]}{[\text{Conc . of lactic acid }]}  = 2.51

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4 0
3 years ago
What is h2o? I’m in 1st grade
Crazy boy [7]

Answer:

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5 0
3 years ago
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Tris is a weak base. The basic form of tris can be written tris0 and the protonated (conjugate acid) form can be written tris. T
Arada [10]

Answer:

a) [Tris0] : [Tris] = 1 : 100

b) Range = 7.1 to 9.1

Explanation:

a) Calculation of ratio of the basic and the acidic forms of tris

pH of a buffer is calculate using Henderson-Hasselbalch equation

pH = pKa+log\frac{Salt}{Acid}

Conjugate acid of Tris dissociated as

Tris \leftrightharpoons Tris0 + H^+

For tris,

Salt or Basic form = tris0

Acid or Acidic form = Tris

pKa = 8.1

pH = 6.1

pH = pKa+log\frac{Tris0}{Tris}

6.1 = 8.1+log\frac{Tris0}{Tris}

log\frac{Tris0}{Tris} = -2

\frac{Tris0}{Tris} = antilog (-2)

\frac{Tris0}{Tris} = 10^{-2}

[Tris0] : [Tris] = 1 : 100

b) Range of Tris

Range of any buffer is:

From (pKa -1) to (pKa+1)

So, range of Tris is:

From (8.1 - 1) to (8.1 +1)

or from 7.1 to 9.1

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3 years ago
KBr will undergo dissociation in solution while benzene will undergo solvation.
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Kbr will undergo dissociation in an aqueous solution. But Benzene will not dissolve in water so it will be a solvent.

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Exhaling air from your lungs
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