Answer:
Explanation:
Moles of sodium
=
130
⋅
g
22.99
⋅
g
⋅
m
o
l
−
1
=
5.65
⋅
m
o
l
.
Now you have the stoichiometric equation:
2
N
a
(
s
)
+
2
H
2
O
(
l
)
→
2
N
a
O
H
(
a
q
)
+
H
2
(
g
)
↑
⏐
If there are
5.65
⋅
m
o
l
of metal, clearly
5.65
⋅
m
o
l
2
dihydrogen gas are evolved......, i.e.
2.83
⋅
m
o
l
H
2
. Typically, in a question like this, you would also be asked to calculate the volume the gas occupies under standard conditions, and the
p
H
of the resultant solution (would it be high, low, neutral?).
<span> I would guess that calcium (Ca), of all the group 2 elements, is most like magnesium (Mg), because it has the most similar size (atomic and ionic radii) to Mg. </span>
Answer:
2Na + 2H20--> 2NaOH+H2
............. this is the ans
Mass after 60 years:
2 kg of cesium-137 will remain after 60.0 years.
What is Half-life?
The duration needed for a quantity to decrease to half of its initial value is known as the half-life.
Given:
N0 = is the initial amount of cesium-137 = 8.0 Kg
N = is the amount remaining after a time = Unknown
t = Duration of cesium-137 decay in 8.0 Kg = 60 years
t1/2 = half-life of cesium-137 = 30.0 years
Formula = N/No = (1/2)^t/t1/2
After putting the value:
N/8= (1/2)^60/30
N/8= (1/2)^2
N/8= 1/4
4N= 8
N= 8/4
N= 2 Kg
As a result, 2 Kg of cesium-137 will be present after 60 years.
Learn more about the half-life here,
brainly.com/question/14018709
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