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Slav-nsk [51]
4 years ago
10

What occurs when chemical bonds break and new bonds form​

Chemistry
2 answers:
7nadin3 [17]4 years ago
4 0
I think energy is released
Margarita [4]4 years ago
4 0
Chemical reactions make and break the chemical bonds between molecules, resulting in new materials as the products of the chemical reaction. ... Breaking chemical bonds absorbs energy, while making new bonds releases energy, with the overall chemical reaction being endothermic or exothermic
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If you were asked to describe metals and magnetism you could say. A. non–paired electrons spin in opposite directions in all met
attashe74 [19]

Answer : Option D) the electrons in some metals pair up to create a magnetic field.


Explanation : Most of the metals are magnetic in nature including some exceptions. When the unpaired electrons get aligned with the magnetic field they posses magnetism. Also there are some paired electrons in metals which align themselves according to the magnetic field and create magnetism in them.

3 0
3 years ago
Read 2 more answers
Glven 4.62 mol of sodium hydroxide, NaOH, how many grams are present?
Vaselesa [24]
1 mole is equal to 1 moles NaOH, or 39.99711 grams.
Hope this helped
3 0
3 years ago
A person driving a car applies the brakes. This produces friction, which stops the car. Into which type of energy is the mechani
antiseptic1488 [7]

Answer: D. Gravitational

Explanation:

3 0
3 years ago
10. If 3.5 kJ of energy are added to a 28.2 g sample of iron at 20°C, what
igor_vitrenko [27]

Answer:

569K

Explanation:

Q = 3.5kJ = 3500J

mass = 28.2g

∅1 = 20°C = 20 + 273 = 293K

∅2 = x

c = 0.449

Q = mc∆∅

3500 = 28.2×0.449×∆∅

3500 = 12.6618×∆∅

∆∅ = 3500/12.6618

∆∅ = 276.4220

∅2 - ∅1 = 276.4220

∅2 = 276.4220 + ∅1

∅2 = 276.4220 + 293

∅2 = 569.4220K

∅2 = 569K

3 0
3 years ago
How much heat is required to raise the temperature of 81.0 g of water from its melting point to its boiling point?
Dovator [93]

Answer:

Specific heat of water = 33.89 KJ

Explanation:

Given:

mass of water = 81 gram

Initial temperature = 0°C

Final temperature = 100°C

Specific heat of water = 4.184

Find:

Required heat Q

Computation:

Q = Mass x Specific heat of water x (Final temperature - Initial temperature)

Q = (81)(4.184)(100-0)

Q = 33,890.4

Specific heat of water = 33.89 KJ

6 0
3 years ago
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