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3 years ago

What elements in the periodic table might combine with oxygen to form magnesium oxide?

1 answer:

3 0

I would guess that calcium (Ca), of all the group 2 elements, is most like magnesium (Mg), because it has the most similar size (atomic and ionic radii) to Mg.

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an underground explosion generates sound waves that travel through solid rock, then through a lake and then air. describe how th

DIA [1.3K]

Answer: sound can slow down, so when it travels through all of that it's muffled and kind of blocked. sound travels at 332 metres per second so it's hard to stop the sound

Explanation:

7 0

3 years ago

The volume of a gas is 450 mL when its pressure is 1.00 atm. If the temperature of the gas does not change, what is the pressure

Fudgin [204]

Ans: 0.225 atm

Given:

Initial volume of gas, V1 = 450 ml = 0.450 L

initial pressure, P1 = 1.00 atm

Final volume, V2 = 2.00 L

To determine:

Final pressure, P2

Explanation:

Based on ideal gas equation:

PV = nRT ----(1)

where P = pressure, V = volume, n = # moles, R = gas constant, T = temp

Under constant, T and n, eq(1) can be expressed as:

PV = constant

(or) P1V1 = P2V2

P2 = P1V1/V2 = 1.00 atm * 0.450 L/2.00 L = 0.225 atm

3 0

3 years ago

Read 2 more answers

If a solution containing 23.81 g of lead(II) acetate is allowed to react completely with a solution containing 7.410 g of sodium

jeka57 [31]

Answer:

The correct answer is 15.80 grams.

Explanation:

The reaction taking place in the given question,

Pb(CH₃COO)₂ + Na₂SO₄ ⇒ PbSO₄ + 2NaCH₃COO

The number of moles can be calculated by using the formula,

n = weight / molecular mass

Based on the given question, the weight of lead (II) acetate is 23.81 grams and the weight of sodium sulfate is 7.410 grams.

The number of moles of Pb(CH₃COO)₂ is,

n = 23.81 g / 325.29 g/mol = 0.0732 moles

The number of moles of Na₂SO₄ is,

n = 7.410 g / 142.04 g/mol = 0.0521 moles

As one mole of lead (II) acetate needs one mole of sodium sulfate. Therefore, 0.0732 moles of lead (II) acetate needs 0.0732 moles of sodium sulfate.

However, as sodium sulfate is less, that is, 0.0521, therefore, Na₂SO₄ is a limiting reactant.

One mole of sodium sulfate produces one mole of PbSO₄. So, 0.0521 moles of Na₂SO₄ produces 0.0521 moles of PbSO₄.

Now the mass of PbSO₄ is,

mass = moles × molecular mass

mass = 0.0521 × 303.26 g/mol

mass = 15.80 grams.

6 0

3 years ago

Sheena wants to measure the volume of a ball that is 24 cm across. How should she set up her equation?

Ksivusya [100]

Answer:

The volume of a ball that is 24 cm across is :

d). v = four-thirds pi 12 cubed

Explanation :

Ball is a sphere and volume of sphere is given by :

$\frac{4}{3}\Pi r^{3}$

r = radius of ball

$r =\frac{24}{2}$

r = 12 cm

Volume is :

$\frac{4}{3}\Pi \times 12^{3}$

8 0

4 years ago

Read 2 more answers

A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate th

Andreas93 [3]

Complete question:

A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate the heat of combustion of methanol in kJ/mol.

Answer:

the heat of combustion of the methanol is 402.31 kJ/mol

Explanation:

Given;

mass of water, $m_w$ = 100 g

initial temperature of water, t₁ = 28 ⁰C

final temperature of water, t₂ = 58 ⁰C

specific heat capacity of water = 4.184 J/g⁰C

reacting mass of the methanol, m = 1.00 g

molecular mass of methanol = 32.04 g/mol

number of moles = 1 / 32.04

= 0.0312 mol

Apply the principle of conservation of energy;

$n\Delta H_{methanol} = Q_{water}\\\\n\Delta H_{methanol} = mc\Delta t\\\\n\Delta H_{methanol} = 100 \times 4.184\times (58-28)\\\\n\Delta H_{methanol} = 12,552 \ J\\\\n\Delta H_{methanol} = 12.552 \ kJ\\\\\Delta H_{methanol} = \frac{12.552}{n} \\\\H_{methanol} = \frac{12.552 \ kJ}{0.0312 \ mol} \\\\\Delta H_{methanol} = 402.31 \ kJ/mol$

Therefore, the heat of combustion of the methanol is 402.31 kJ/mol

5 0

3 years ago