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3 years ago

How many grams of NH3 can be produced from 2.93mol of N2 and excess H2?

1 answer:

mote1985 [20]3 years ago

7 0

1 mol of N2 is 28 gms, thus, 2.93mol is 84 gms.

According to the equation-

N (2 + 3H (2) = 2NH(3)

28gms (1mol) of N2 produces 34gms of NH3

so, 84gms of N2 will produce:

28gms of N2----->34gms of NH3
84gms of N2-----> 28/84 = 34 / x

x= (34*84) / 28

Answer: 102gms

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Determine the molality of a solution of methanol dissolved in ethanol for which the mole fraction of methanol is 0.135. Give you

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Explanation:

We are given:

Mole fraction of methanol = 0.135

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$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

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Putting values in above equation, we get:

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