Answer:
13.9atm
Explanation:
Use Boyle's Law: P1V1 = P2V2
Manipulate the equation: P2 = P1V1/V2
Substitute the values: P2 = (1.31atm)(5.51L)/0.520L
P2 = 13.88096atm
Optionally round to 3 sig figs to get 13.9atm
The total number of moles of solute particles present in 1L (exact) of aqueous 0.057 m hno3 is 0.166 mol
Initial moles of HNO3 = 1Lx 0.083 mol HNO3/1 L
The HNO3 is a strong acid that can be completely dissociated in the following way.
HNO3→H + NO
1 mol 1 mol 1 mol
The HNO3 is dissociated into two particles (Kt and NO3). So that,
total moles particles = 0.083 mol (K) + 0.083 mol (NO) = 0.166 mol
The number of moles of solute = mass of solute ÷ molar mass of solute, where mass is measured in grams and molar mass (defined as the mass of one mole of a substance in grams) is measured in g/mol.
Learn more about moles of solute here brainly.com/question/2306123
#SPJ4
Answer:
0.481 M
Explanation:
The molarity ratio looks like this:
Molarity = moles / volume (L)
Since you have been given both the mass and volume, you can plug them into the equation to find the molarity.
Molarity = moles / volume
Molarity = 0.650 moles / 1.35 L
Molarity = 0.481 M
Answer:
0.35moles
Explanation:
when 156g of Al reacts with 2molesof Al2O3 then 27g of Al reacts with what then u cross multiply and solve ur answer