How many molecules of N2O5 are there in 175 grams of N2O5?

Chemistry

1 answer:

Vaselesa [24]1 year ago

6 0

Answer:

9.76 x 10²³molecules

Explanation:

Given parameters:

Mass of N₂O₅ = 175gram

Unknown:

Number of molecules = ?

Solution:

To find the number of molecules contained in the given mass, we need to find the number of moles of N₂O₅ first.

Number of moles = $\frac{mass}{molar mass}$

Molar mass of N₂O₅ = 2(14) + 5(16) = 108g/mol

Number of moles = $\frac{175}{108}$ = 1.62moles

Now;

1 mole of a substance = 6.02 x 10²³ molecules

1.62 mole of N₂O₅ = 1.62 x 6.02 x 10²³ = 9.76 x 10²³molecules

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Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou

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Answer:

$4.36~g~XY$

Explanation:

In this case, we can start with the reaction:

$2X + Y_2~->~2XY$

If we check the reaction, we will have 2 X and Y atoms on both sides. So, the reaction is balanced. Now, the problem give to us two amounts of reagents. Therefore, we have to find the limiting reagent. The first step then is to find the moles of each compound using the molar mass:

$3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X$

$4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2$

Now, we can divide by the coefficient of each compound (given by the balanced reaction):

$\frac{0.04~mol~X}{1}=~0.04$

$\frac{0.0875~mol~Y_2}{2}=0.04375$

The smallest value is for "X", therefore this is our limiting reagent. Now, if we use the molar ratio between "X" and "XY" we can calculate the moles of XY, so:

$0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY$

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol $Y_2$ = 48 g $Y_2$ (therefore 1 mol Y = 24 g Y). With this in mind the molar mass of XY would be 85+24 = 109 g/mol. With this in mind: