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2 years ago

How many molecules of N2O5 are there in 175 grams of N2O5?

Chemistry

1 answer:

Vaselesa [24]2 years ago

6 0

Answer:

9.76 x 10²³molecules

Explanation:

Given parameters:

Mass of N₂O₅ = 175gram

Unknown:

Number of molecules = ?

Solution:

To find the number of molecules contained in the given mass, we need to find the number of moles of N₂O₅ first.

Number of moles = $\frac{mass}{molar mass}$

Molar mass of N₂O₅ = 2(14) + 5(16) = 108g/mol

Number of moles = $\frac{175}{108}$ = 1.62moles

Now;

1 mole of a substance = 6.02 x 10²³ molecules

1.62 mole of N₂O₅ = 1.62 x 6.02 x 10²³ = 9.76 x 10²³molecules

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3 years ago

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Read 2 more answers

A solution is prepared by dissolving 42.0 g of glycerin, C3H8O3, in 186 g of water with a final volume of 200.0 mL. a. Calculate

trapecia [35]

Answer:

For a: The molality and molarity of the given solution is 2.45m and 2.28 M respectively.

For b: The molarity of the solution when more water is added is 0.912 M

Explanation:

For a:

To calculate the molality of solution, we use the equation:

$Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute $(C_3H_8O_3)$ = 42.0 g

$M_{solute}$ = Molar mass of solute $(C_3H_8O_3)$ = 92.093 g/mol

$W_{solvent}$ = Mass of solvent (water) = 186 g

Putting values in above equation, we get:

$\text{Molality of }C_3H_8O_3=\frac{42\times 1000}{92.093\times 186}\\\\\text{Molality of }C_3H_8O_3=2.45m$

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .....(1)

We are given:

Molarity of solution = ?

Molar mass of $(C_3H_8O_3)$ = 92.093 g/mol

Volume of solution = 200 mL

Mass of $(C_3H_8O_3)$ = 42 g

Putting values in above equation, we get:

$\text{Molality of }C_3H_8O_3=\frac{42\times 1000}{92.093\times 200}\\\\\text{Molality of }C_3H_8O_3=2.28M$

Hence, the molality and molarity of the given solution is 2.45m and 2.28 M respectively.

For b:

Now, the 300 mL water is added to the solution. So, the total volume of the solution becomes (200 + 300) = 500 mL

Using equation 1 to calculate the molarity of solution, we get:

Molar mass of $(C_3H_8O_3)$ = 92.093 g/mol

Volume of solution = 500 mL

Mass of $(C_3H_8O_3)$ = 42 g

Putting values in equation 1, we get:

$\text{Molality of }C_3H_8O_3=\frac{42\times 1000}{92.093\times 500}\\\\\text{Molality of }C_3H_8O_3=0.912M$

Hence, the molarity of the solution when more water is added is 0.912 M

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