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2 years ago

8

What is the value of the expression i To the power of 1 times I to the power of 2 times I to the power of 3 times I to the power

of 4

1 answer:

nalin [4]2 years ago

6 0

Answer:

-1

Step-by-step explanation:

$i^1\cdot i^2\cdot i^3\cdot i^4= \\\\i^{1+2+3+4}= \\\\i^{10}= \\\\-1$

Hope this helps!

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The 20% tip on<br> a $42 meal

blondinia [14]

Answer:

$8.4 hskshskshsjsjjsj

3 0

2 years ago

How to solve this <br><br> 4x-3(x-2)=21

Natasha_Volkova [10]

We can start by getting rid of parenthesis:

4x-3x+6=21

Then we can combine like terms:

x=21-6

x=15

So our end product is x=15.

Hope I helped soz if I'm wrong ouo.

~Potato.

Copyright Potato 2019.

4 0

3 years ago

One canned juice drink is 25%orange juice; another is 10%orange juice. how many liters of each should be mixed together in or

sertanlavr [38]

   Qty    · % = Total
Drink 1:    x .25 = .25x
Drink 2:   15 - x .10 = .10(15 - x)
Mixture: 15 .21 = .25x + .10(15 - x)

   (15)(.21)   =    .25x + 1.5 - .10x
   3.15 =    .15x + 1.5
   1.65 = .15x
   11    = x

Drink 1 (25%) is 11 liters
Drink 2 (10%) is 15 - 11 = 4 liters

6 0

3 years ago

Simplify 2^-6 times 2^3

IgorC [24]

Answer:

(2^-6)*(2^3)

=2^(-6+3)

=2^-3

=1/(2^3)

=1/8

3 0

2 years ago

Read 2 more answers

Jared has 12 more comic books than Zoe. If they have 28 comic books

ZanzabumX [31]

Answer:

20 comic books

Step-by-step explanation:

Let us first <u>set up a variable</u>, x, for the number of books that Zoe has. If Jared has 12 more comics than Zoe, he would have x+12 books.

Given that Zoe and Jared have a total of 28 comic books, let us write an <u>equation</u> and solve for x:

$x+x+12=28\\2x+12=28$

Now that we have a <u>simplified</u> version of the equation, let us solve for x by <u>isolating the variable</u> on the left side:

$2x=28-12\\2x=16\\x=8$

We now know that x=8, and also that Jared has x+12 books. To find the number of comic books Jared has, let us <u>add</u> 12 to x:

$x+12=\\8+12=\\20\\$

Therefore, Jared has 20 comic books.

<em>I hope this helps! Please let me know if you have any further questions :)</em>

4 0

2 years ago