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Vesnalui [34]
3 years ago
15

The charger for your electronic devices is a transformer. Suppose a 60 HzHz outlet voltage of 120 VV needs to be reduced to a de

vice voltage of 3.0 VV. The side of the transformer attached to the electronic device has 60 turns of wire.How many turns are on the side that plugs into the outlet?
Physics
1 answer:
photoshop1234 [79]3 years ago
4 0

Answer:

2400 turns

Explanation:

Applying

Vs/Vp = Ns/Np.................. Equation 1

Where Vs = Secondary voltage of the transformer, Vp = Primary voltage of the transformer, Ns = number of turns in the secondary side, Np = Number of turns in the primary side.

First we make Np the subject of the equation

Np = NsVp/Vs................. Equation 2

Given: Ns = 60 turns, Vp = 120 v Vs = 3.0 V

Substitute into equation 2

Np = 60(120)/3

Np = 2400 turns

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Answer:

a

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Explanation:

From the question we are told that

             The  length line   above the ground  is  R = 20m

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Generally magnetic field strength is mathematically represented as

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   So the percentage would be

                           = \frac{Magnetic \ Field \ Intensity \ Of  \ Line}{Earth's \ Magnetic \ Field} * 100

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2 years ago
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In this case we have two situations:

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Substituting \frac{GM^2}{r^2}  found in (7) in (6):

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F_{2}=\frac{12}{16}F_{1}   (9)

Simplifying, we finally get the expression for F_{2}  in terms of F_{1} :

F_{2}=\frac{3}{4}F_{1}  

5 0
3 years ago
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