On a calm day with no wind, you can run a 1500-m race at a velocity of 4.0 m/s. If you run the same race on a day when you have
2 answers:
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Answer:
Approximately , assuming that the gravitational field strength is
.
Explanation:
Let denote the required angular velocity of this Ferris wheel. Let
denote the mass of a particular passenger on this Ferris wheel.
At the topmost point of the Ferris wheel, there would be at most two forces acting on this passenger:
- Weight of the passenger (downwards),
, and possibly
- Normal force
that the Ferris wheel exerts on this passenger (upwards.)
This passenger would feel "weightless" if the normal force on them is - that is,
.
The net force on this passenger is . Hence, when
, the net force on this passenger would be equal to
.
Passengers on this Ferris wheel are in a centripetal motion of angular velocity around a circle of radius
. Thus, the centripetal acceleration of these passengers would be
. The net force on a passenger of mass
would be
.
Notice that . Solve this equation for
, the angular speed of this Ferris wheel. Since
and
:
.
.
The question is asking for the angular velocity of this Ferris wheel in the unit , where
. Apply unit conversion:
.