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dedylja [7]
1 year ago
13

On a calm day with no wind, you can run a 1500-m race at a velocity of 4.0 m/s. If you run the same race on a day when you have

a constant headwind that slows your speed by 2.0 m/s, how much time would it take you to finish the race
Physics
2 answers:
Galina-37 [17]1 year ago
8 0

Answer:

The required time is 750 s.

Explanation:

The velocity of the man gets slowed by 2.0 m/s when the wind is blowing.

Therefore the speed of the man on the day of wind is (4.0-2.0)=2.0 m/s.

The time, speed and distance are related by the equation,

t=v/d

Given v= 2 m/s and d=1500 m.

The required time is,

t=1500/2

t=750 s

Learn more about distance formula.

brainly.com/question/11954435

#SPJ10

lesantik [10]1 year ago
3 0

Answer:

The time taken to finish the race is 750 s.

Explanation:

The velocity of the person on the day of wind is slowed down by 2.0 m/s. So the person's velocity on the day of wind is 4-2=2 m/s.

The relation between time, speed and distance is t=v/d

Given d=1500 m and calculated v= 2 m/s.

t=1500/2

t=750 s.

Learn more about distance formula.

brainly.com/question/11954435

#SPJ10

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A bullet with a mass of 4.5 g is moving with a speed of 300 m/s (with respect to the ground) when it collides with a rod with a
Law Incorporation [45]

Answer:

ω = 5.41 rad/s

Explanation:

Since the rod is rotating around its axis, angular momentum will play part in this question.

The conservation of angular momentum implies that

L_1 = L_2

So, the initial angular momentum is

L_1 = m_b v_b \frac{L}{4} = (4.5\times 10^{-3}~{\rm kg})(300~{\rm m/s})(\frac{0.25}{4}~{\rm m}) = 0.0844~{\rm kg.m^2/s}

The final angular momentum includes the rod and the bullet together. So,

L_2 = I\omega\\I = I_{rod} + I_{bullet} = \frac{1}{12}m_r L^2 + m_b(\frac{L}{4})^2 = \frac{1}{12}3(0.25)^2 + (4.5\times 10^{-3})(\frac{0.25}{4})^2 = 0.0156~{\rm kg.m^2}\\L_2  = L_1 = I\omega\\0.0844 = 0.0156\omega\\\omega = 5.41~{\rm rad/s}

5 0
3 years ago
Laboratory measurements show hydrogen produces a spectral line at a wavelength of 486.1 nanometers (nm). A particular star's spe
belka [17]

Answer:

It means that the star is moving towards us.

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The star is moving toward us; shift to a shorter wavelength. A shorter wavelength means a shift to the blue end of the spectrum (a blueshift) so that the object is moving toward us.

4 0
3 years ago
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1. A 0.40 kg ball is launched at a speed of 16 m/s from a 22 m cliff.
Masja [62]

Answer:

51.2 J, 86.2 J, 137.4 J

Explanation:

The kinetic energy of the ball is given by:

K=\frac{1}{2}mv^2

where

m = 0.40 kg is its mass

v = 16 m/s is its speed

Substituting,

K=\frac{1}{2}(0.40)(16)^2=51.2  J

The potential energy of the ball is given by

U=mgh

where

m = 0.40 kg

g=9.8 m/s^2 is the acceleration of gravity

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Substituting,

U=(0.40)(9.8)(22)=86.2 J

Finally, the total mechanical energy is the sum of the kinetic energy and the potential energy:

E=K+U=51.2 + 86.2=137.4 J

4 0
3 years ago
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8_murik_8 [283]
This is simply F=ma so 70N/30m/s^2 will give you the max mass which would be in kg, and the mass would be 2.333333kg a very light plane I might say
4 0
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The atoms of carbon 12 contain 6 neutrons while the atoms of carbon 14 contain 8 neutrons
4 0
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