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Assoli18 [71]
3 years ago
5

A car goes from a speed of 10m/s to 30m/s over 4s. If the car has a mass of 1000kg, How strong is the force pushing the car forw

ard?
Physics
1 answer:
dusya [7]3 years ago
5 0

Answer:

i think ww

Explanation:

i think we need to calculate net force which is:

net force=m.a

..nf=1000kg×30m/s

therefore net force will be the answer you get whwn you multiply those two

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44. ( John weighs 80 kg, and eats a 1,000 J candy bar. If his
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John can run with the velocity of 5 m/s

Explanation:

  • Kinetic energy is defined as the energy is being used to do an activity, basically energy associated with the motion of objects in the universe.
  • The formula used to find the kinetic energy of an object is k = \frac{1}{2} mv^{2} where as k represented as kinetic energy, m is the mass of the object and v is the velocity of the given object.
  • Here, to find the answer we have to re-write the equation as v = \sqrt[2]{\frac{2 k}{m} }
  • Given, the mass of the object, here it is John = 80 kg, energy needs to be converted to kinetic energy, k = 1000  J.
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3 years ago
A sound can be ________ or _________.
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A.
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A pickup truck is carrying a 10.0 kg toolbox, but the tailgate of the truck is missing, so the box can slide out if it starts mo
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Explanation: Please see the attachments below

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3 years ago
Suppose that in a lightning flash the potential difference between a cloud and the ground is 0.96×109 V and the quantity of char
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(a) 2.98\cdot 10^{10} J

The change in energy of the transferred charge is given by:

\Delta U = q \Delta V

where

q is the charge transferred

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Here we have

q=31 C

\Delta V = 0.96\cdot 10^9 V

So the change in energy is

\Delta U = (31 C)(0.96\cdot 10^9 V)=2.98\cdot 10^{10} J

(b) 7921 m/s

If the energy released is used to accelerate the car from rest, than its final kinetic energy would be

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m = 950 kg is the mass of the car

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Here the energy given to the car is

K=2.98\cdot 10^{10} J

Therefore by re-arranging the equation, we find the final speed of the car:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(2.98\cdot 10^{10})}{950}}=7921 m/s

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3 years ago
The tip of a fan blade is 0.61 m from the center of the fan. The fan turns at a constant speed and completes 2 rotations every 1
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v = ωr
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7 0
3 years ago
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