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elena-14-01-66 [18.8K]
3 years ago
5

A ringing bell sends sound waves in all directions places sides

Physics
1 answer:
Strike441 [17]3 years ago
4 0

Answer:

direction

Explanation:

because particles surround the bell, so when the bell vibrates, it causes particles surrounding it to vibrate back and forth vigorously. as these particles vibrate they collide with the neighbouring particles, passing on the energy.

hope this is what you are asking, if not please report it so that someone else gets to try it.

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When two point charges are a distance dd part, the electric force that each one feels from the other has magnitude F.F . In orde
Harman [31]

Answer:

In order to make this force twice as strong, F' = 2 F, the distance would have to be changed to half i.e. r' = r/2.

Explanation :

The electric force between two point charges is directly proportional to the product of charges and inversely proportional to the square of the distance between charges. It is given by :

F=\dfrac{kq_1q_2}{r^2}

r is the separation between charges  

F\propto \dfrac{1}{r^2}

r=\sqrt{\dfrac{1}{F}}

If F'= 2F

r'=\dfrac{1}{\sqrt{2F} }

In order to make this force twice as strong, F' = 2 F, the distance would have to be changed to half i.e. r'=\dfrac{1}{\sqrt{2F} }. Hence, this is the required solution.                                                                                    

6 0
3 years ago
A rocket starts from rest and moves upward from the surface of the earth. For the first 10s of its motion, the vertical accelera
Naily [24]
Since the rocket’s acceleration is 3.00 m/s^3 * t, its acceleration is increasing at the rate of 3 m/s^3 each second. The equation for its velocity at a specific time is the integral of the acceleration equation. 

<span>vf = vi + 1.5 * t^2, vi = 0 </span>
<span>vf = 1.5 * 10^2 = 150 m/s </span>
This is the rocket’s velocity at 10 seconds. The equation for its height at specific time is the integral velocity equation

<span>yf = yi + 0.5 * t^3, yi = 0 </span>
<span>yf = 0.5 * 10^3 = 500 meters </span>
<span>This is the rocket’s height at 10 seconds. </span>

<span>Part B </span>
<span>What is the speed of the rocket when it is 345 m above the surface of the earth? </span>
<span>Express your answer with the appropriate units. </span>


<span>Use the equation above to determine the time. </span>

<span>345 = 0.5 * t^3 </span>
<span>t^3 = 690 </span>
<span>t = 690^⅓ </span>
<span>This is approximately 8.837 seconds. Use the following equation to determine the velocity at this time. </span>

<span>v = 1.5 * t^2 = 1.5 * (690^⅓)^2 </span>
<span>This is approximately 117 m/s. </span>


<span>The graph of height versus time is the graph of a cubic function. The graph of velocity is a parabola. The graph of acceleration versus time is line. The slope of the line is the coefficient of t. This is a very different type of problem. For the acceleration to increase, the force must be increasing. To see what this feels like slowly push the accelerator pedal of a car to the floor. Just don’t do this so long that your car is speeding!!</span>
3 0
4 years ago
Read 2 more answers
A centrifuge has an angular velocity of 3,000 rpm, what is the acceleration (in unit of the earth gravity) at a point with a rad
Anna71 [15]

Answer:

a_{r} = 1006.382g \,\frac{m}{s^{2}}

Explanation:

Let suppose that centrifuge is rotating at constant angular speed, which means that resultant acceleration is equal to radial acceleration at given radius, whose formula is:

a_{r} = \omega^{2}\cdot R

Where:

\omega - Angular speed, measured in radians per second.

R - Radius of rotation, measured in meters.

The angular speed is first determined:

\omega = \frac{\pi}{30}\cdot \dot n

Where \dot n is the angular speed, measured in revolutions per minute.

If \dot n = 3000\,rpm, the angular speed measured in radians per second is:

\omega = \frac{\pi}{30}\cdot (3000\,rpm)

\omega \approx 314.159\,\frac{rad}{s}

Now, if \omega = 314.159\,\frac{rad}{s} and R = 0.1\,m, the resultant acceleration is then:

a_{r} = \left(314.159\,\frac{rad}{s} \right)^{2}\cdot (0.1\,m)

a_{r} = 9869.588\,\frac{m}{s^{2}}

If gravitational acceleration is equal to 9.807 meters per square second, then the radial acceleration is equivalent to 1006.382 times the gravitational acceleration. That is:

a_{r} = 1006.382g \,\frac{m}{s^{2}}

6 0
3 years ago
The planet earth consists of land formations, large masses of water, gases in the atmosphere, and living organisms.
andrew-mc [135]
A. 
The planet contains matter and energy so it is a system.
8 0
3 years ago
When recyclable materials are sent to a recycling plant, they are often not sorted in any particular way. Plastic materials migh
4vir4ik [10]

Answer:

by applying a magnetic force to recycled materials

8 0
3 years ago
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