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3 years ago

When an electric current flows through a long conductor, each free electron moves

2 answers:

8 0

<span>When an electric current flows through a long conductor, each free electron moves from one end of the other end. When an electric field is applied to a conductor (a wire) the free electrons of the conductor are subject to an electric force which will cause the electrons to move. Given that the electrons are negatively charged they will move counter-wise the field.. Each end of the wire is attached to one pole or end of a battery (or generator of electricity) then the electrons will move form the end joined to the negative pole toward the end attached to positive pole.</span><span />

pentagon [3]3 years ago

4 0

D) through a relatively short distance.

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Make a sketch of the radius of gyration of a polymer chain vs. the degree of polymerization N as it would appear on a log-log sc

zvonat [6]

Answer:

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Explanation:

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4 0

3 years ago

Jeff is a landscaping contractor and lifts a rock weighing 600 pounds by wedging a board under the rock. Jeff weighs 150 pounds

jonny [76]

Answer: 4

The mechanical advantage is the ratio of the force exerted by the object to the force applied to do work on it.

Here, Jeff tried to lift a rock weighing 600 pounds by wedging board under the rock. Jeff who weighs 150 pounds uses all his weight to exert force on lever and lift rock.

Mechanical advantage, $M.A.=\frac{weight\hspace{1mm}of\hspace{1 mm}rock}{weight\hspace{1mm}of\hspace{1 mm}Jeff}=\frac{600 pounds}{150 pounds}=4.$

Therefore, the mechanical advantage that lever provided to Jeff in lifting rock is 4.

6 0

3 years ago

Read 2 more answers

When the medium is uniform, how do light waves pass through it?

LekaFEV [45]

The correct answer is, A) Straight line motion

I took the quiz

8 0

3 years ago

An object is 30 cm in front of a converging lens with a focal length of 10 cm. Use ray tracing to determine the location of the

poizon [28]

Answer:

Inverted

Real

Explanation:

u = Object distance = 30 cm

v = Image distance

f = Focal length = 10 cm

Lens Equation

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{10}-\frac{1}{30}\\\Rightarrow \frac{1}{v}=\frac{1}{15}\\\Rightarrow v=15\ cm$

As, the image distance is positive the image is real and forms on the other side of the lens

$m=-\frac{v}{u}\\\Rightarrow m=-\frac{-15}{30}\\\Rightarrow m=-0.5$

As, the magnification is negative the image is inverted

3 0

3 years ago

Conservation of Momentum<br> No one likes you little trolls please send an actual answer

Olin [163]

Hello!

This is an example of an inelastic collision, where the two objects "stick" to each other after their collision. (The Goalkeeper CATCHES the puck).

We can write out the conservation of momentum formula:

m1vi + m2vi = m1vf + m2vf

Let:

m1 = mass of puck

m2 = mass of the goalkeeper

We know that the initial velocity of the goalkeeper is 0, so:

m1vi + m2(0) = m1vf + m2vf

m1vi = m1vf + m2vf

The final velocities will be the same, so:

m1vi = (m1 + m2)vf

Plug in the given values:

(0.16)(40)/ (0.16 + 120) = vf ≈ 0.0533 m/s

Using the equation for momentum:

p = mv

The object with the LARGER mass will have the greater momentum. Thus, the Goalkeeper has the largest momentum as p = mv; a greater mass correlates to a greater momentum since the velocity is the same between the two objects. The puck would have a momentum of p = (.16)(0.0533) = 0.008528 kgm/s, whereas the goalkeeper would have a momentum of

p = (120)(0.0533) = 6.396 kgm/s.

3 0

2 years ago