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Bingel [31]
3 years ago
13

Find the momentum of a 120 g snowball that is rolling with a velocity of 8.9 m/s. Express your answer in two significant figures

.
show your work pls
Chemistry
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

30kg m/s.

Explanation:

30 kg m/s

Explanation

Momentum = Mass × Velocity = 10 kg × 3 m/s = 30 kg m/s

Its momentum is 30 kg m/s.

Explanation:

Momentum is defined by the following equation:

p=mv

where m is the mass of the object in kilograms, v is the velocity of the object in meters per second

p=10 kg⋅3 m/s

=30 kg m/s

Also nice photo.

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The question is incomplete. Her eis the complete question.

Steam reforming methane  (CH4) produces "synthesis gas", a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 125L tank with 20 mol of methane gas and 10 mol of water vapor at 38°C. He then raises the temperature, and when the mixture has come to equilibrium measures the amount of gas hydrogen to be 18 mol. Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to significant digits.

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<u>Molarity of H2</u>:

H2 = \frac{18}{125} = 0.144M

According to the chemical reaction, the combination of 1 mol of each reagents produces 1 mol of CO and 3 mols of H2, so, for the products, the ratio is 1:3.

<u>Molarity of CO</u>:

CO = \frac{0.144}{3} = 0.048M

For the reagents, the proportion is 1:1, but they had an initial concentration, so, when in equilibrium, the concentration will be:

<u>Molarity of CH4</u>:

CH4 = 0.16 - 0.048 = 0.112M

<u>Molarity of H2O</u>:

H20 = 0.08 - 0.048 = 0.032M

The equilibrium constant is given by:

K_{c} = \frac{[CO][H_{2}]^{3} }{[CH_{4}][H_{2}O ] }

K_{c} = \frac{0.048.0.144^{3} }{0.112.0.032}

K_{c} = 2.10^{-2}

The concentration equilibrium constant for the process is K_{c} = 2.10^{-2}.

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