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Musya8 [376]
3 years ago
7

20 POINTS!

Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

Explanation:

N₂O₄

Nitrogen tetroxide.

SO₃

Sulfur trioxide

NO

Nitrogen monoxide

NO₂

nitrogen dioxide

As₂O₅

Arsenic pentoxide

PCl₃

Phosphorus trichloride

CCl₄

Carbon tetrachloride or tetrachloromethane

H₂O

Water

SeF₆

Selenium hexafluoride. Six fluorine atoms are attached with selenium atom.

N₂O₄

Dinitrogen tetroxide. It is reddish-brown liquid.

SO₃

Sulfur trioxide

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LenaWriter [7]

Answer:

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Explanation:

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3 years ago
You only have 15g of sodium to use for this reaction. how much copper(ii must you combine with the sodium to isolate the maximum
Eva8 [605]
The balanced chemical reaction is:

<span>CuCl2 + 2Na → 2NaCl + Cu 

We are given the amount of sodium to be used up in the reaction. This will be the starting point for our calculations.

15 g Na ( 1 mol / 22.99 ) ( 1 mol Cul2 / 2 mol Na ) (134.45 g / 1 mol ) = 43.86 g CuCl2 needed to be able to obtain the maximum amount of copper.</span>
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What mass of H2SO4 is contained in 60.00 mL of a 5.85 M solution of sulfuric acid
strojnjashka [21]

First, we have to calculate the number of moles of H2SO4 in the solution:

V=60 mL = 0.06 L

c=5.85 mol/L

n=V×c=0.06×5.85=0.351 mol

Then we need to find the molar mass of H2SO4:

2×Ar(H) + Ar(S) + 4×Ar(O) =

=2 + 32 + 64 = 98 g/mol

Finally, we need to find the mass of H2SO4:

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5 0
3 years ago
1.Which is the lowest level of organization for the system in a human
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5 0
3 years ago
What is the molarity (M) of .5 liter of a solution that has 205 g of NaCl dissolved in it?
jeka94

Answer:

<h2>Molarity = 7 mol / L</h2>

Explanation:

Since the mass of NaCl and it's volume has been given we can find the molarity by using the formula

<h3>C =  \frac{m}{M \times v}</h3>

where

C is the molarity

m is the mass

M is the molar mass

v is the volume

From the question

v = 0.5 L

m = 205 g

We must first find the molar mass and then substitute the values into the above formula

M( Na) = 23 , M( Cl) = 35.5

Molar mass of NaCl = 23 + 35.5 =

58.5 g/mol

So the molarity of NaCl is

C =  \frac{205}{0.5  \times 58.5}  \\ C =  \frac{205}{29.25}

C = 7.00854

We have the final answer as

<h3>Molarity = 7 mol / L</h3>

Hope this helps you

8 0
3 years ago
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