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Musya8 [376]
4 years ago
7

20 POINTS!

Chemistry
1 answer:
11Alexandr11 [23.1K]4 years ago
4 0

Answer:

Explanation:

N₂O₄

Nitrogen tetroxide.

SO₃

Sulfur trioxide

NO

Nitrogen monoxide

NO₂

nitrogen dioxide

As₂O₅

Arsenic pentoxide

PCl₃

Phosphorus trichloride

CCl₄

Carbon tetrachloride or tetrachloromethane

H₂O

Water

SeF₆

Selenium hexafluoride. Six fluorine atoms are attached with selenium atom.

N₂O₄

Dinitrogen tetroxide. It is reddish-brown liquid.

SO₃

Sulfur trioxide

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scientific notation

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Which of the following can undergo metamorphosis?
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Answer: None of the above

Explanation: It is not possible for any of these animals to undergo metamorphosis.

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I don't really understand this worksheet question.​
Citrus2011 [14]
25/2 and 96/X
CROSS MULTIPLY.

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3 0
3 years ago
Rank these acids according to their expected pKa values.
givi [52]

Answer:

According to their expected pKa values, the order of those acids should be:

1- Cl2CHCOOH is the strongest acid and the lowest pKa.

2- ClCH2COOH is a strong acid, but no more than the first. Medium pKa value.

3- ClCH2CH2COOH is a strong acid, but no more than the two previous acids. High pKa value.

4- CH3CH2COOH  is the weakest acid, so the highest pKa value.

Explanation:

The pKa values are the negative logarithm of dissociation constant. It represents the relative strengths of the acids. Stronger acids show smaller pKa values and weak acids present larger pKa value. The stronger the acid, the weaker it's the conjugate base. The larger the pKa of the conjugate base, the stronger the acid. The strength of an acid is inversely related to the strength of its conjugate.

Conjugate bases are the substance that has one less proton than the parent acid. The conjugate base of the acid presented in the problem are:

ClCH2COOH -> ClCH2COO-  + H+

ClCH2CH2COOH -> ClCH2CH2COO- + H+

CH3CH2COOH -> CH3CH2COO- + H+

Cl2CHCOOH -> Cl2CHCOO - + H+

Cl2CHCOOH. The negative charge presented on its conjugate base is by resonance and inductive effect. This is the strongest acid.

ClCH2COOH. A negative charge is stabilized by resonance and electron-withdrawing but only one atom is present. So this acid is less strong than the first one.

ClCH2CH2COOH. The negative charge is stabilized by resonance and electron-withdrawing atom but the effect is less compared to the two acids showed previously.

CH3CH2COOH. The negative charge is stabilized by resonance and destabilized due to CH3 group. This is the weakest acid among the problem.

Stronger acids have smaller pKa values and weak acids have larger pKa values. Due to the information present in this problem, Cl2CHCOOH is the strongest acid and the lowest pKa. CH3CH2COOH is the weakest acid, so the highest pKa value.

Finally, we can conclude that according to their expected pKa values, the order of those acids should be:

1- Cl2CHCOOH is the strongest acid and the lowest pKa.

2- ClCH2COOH is a strong acid, but no more than the first. Medium pKa value.

3- ClCH2CH2COOH is a strong acid, but no more than the two previous acids. High pKa value.

4- CH3CH2COOH  is the weakest acid, so the highest pKa value.

3 0
3 years ago
Which of the following is not a correct chemical equation for a double displacement reaction?
Ivahew [28]

i just took the test the answer is B

4 0
3 years ago
Read 2 more answers
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