Percent yield represents to what extent the reaction runs to completion. In this, the theoretical yield is 50 grams (100% completion).
To calculate percent yield, divide the actual by the theoretical. In doing so, the percent yield is 88% (44/50).
Answer:
B is the answer
Explanation:
Because it a molecular mass of one
Answer:
92.6 g.
Explanation:
- The balanced equation is:
CaC₂ + N₂ → CaCN₂ + C.
- It is clear that 1.0 mole of CaC₂ reacts with 1.0 mole of N₂ to produce 1.0 mole of CaCN₂ and 1.0 mole of C.
- We need to calculate the no. of moles of 265.0 g of CaCN₂ produced using the relation:
n = mass / molar mass = (265.0 g) / (80.102 g/mol) = 3.308 mol.
- We should get the no. of moles of N₂ needed to produce 3.308 mol of CaCN₂.
∵ 1.0 mole of N₂ produces → 1.0 mole of CaCN₂.
<em>∴ 3.308 mole of N₂ produces → 3.308 mole of CaCN₂.</em>
- Now, we can get the grams of N₂ consumed to produce 265.0 g of CaCN₂:
∴ The grams of N₂ = n x molar mass = (3.308 mole)(28.0 g/mol) = 92.63 g = 92.6 g.
The answer would be absorbed
Answer:
C
Explanation:
It is letter C since you are currently experimenting to see if by the amount of rainfall it gets it can <em><u>grow</u></em><em><u> </u></em><em><u>more</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>less</u></em>. So you control the amount of rain