A sample from solution a and solution b were each tested with blue colored glucose indicator solution before the solutions were
placed in the beaker which row represents the results
1 answer:
With the given problem you gave here, I can't answer the question because I need more details. Luckily, I found a similar problem that's provided with a diagram and a table shown in the attached picture.
This test is called the Benedict's test which is used as test for presence of sugars. If the solution contains sugar, like glucose, the solution would turn from blue to red. If not, it would stay blue. <em>Therefore, the correct results would be that in row 3.</em>
This test is called the Benedict's test which is used as test for presence of sugars. If the solution contains sugar, like glucose, the solution would turn from blue to red. If not, it would stay blue. <em>Therefore, the correct results would be that in row 3.</em>
You might be interested in
Answer:
The answers are;
1. 8.2 liters
2. 1214.84 ml
3. 318.027 K
4. 4.00 l.
Explanation:
1. Boyle's law states that the volume of given mass of gas is inversely proportional to its pressure at constant temperature
that is
P₁·V₁ = P₂·V₂
Where:
P₁ = Initial pressure = 40.0 mm Hg
V₁ = Initial volume = 12.3 liters
P₂ = Final pressure = 60.0 mm Hg
V₂ = Final volume = Required
From P₁·V₁ = P₂·V₂, V₂ is given by
= 8.2 l
The volume reduces to V₂ = 8.2 liters
2. Here Charles law states that
T₁ = Initial temperature = 27.0 °C = 300.15 K
V₁ = Initial volume = 900.0 mL
T₂ = Final temperature = 132.0 °C = 405.15 K
V₂ = Final volume = Required
Therefore =
= 1214.84 ml
V₂ = 1214.84 ml
3. Gay-Lussac's Law states that
Where:
P₁ = Initial pressure = 15.0 atmospheres
T₁ = Initial temperature = 25.0 °C = 298.15 K
P₂ = Final pressure = 16.0 atmospheres
T₂ = Final temperature = Required
∴
= = 318.027 K
T₂ = 318.027 K
4. Avogadro's law states that,
Equal volume of all gases at the same temperature and pressure contain equal number of molecules.
Therefore if 5.00 moles of gas occupies 2.00 l volume, then
1 moles will occupy 2.00/5 l volume and
10 moles will occupy 2.00/5 × 10 or 4.00 l volume.