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katrin [286]
4 years ago
9

Which element has the least metallic character among Li,Be,Na and Mg

Chemistry
1 answer:
dem82 [27]4 years ago
7 0
The element that has the least is na
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Elvis flew his jet 2100 miles at an average speed of 350 mph how long did Elvis trip take
SpyIntel [72]
735000 is the answer .....................
8 0
3 years ago
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
astraxan [27]

Answer:

It will take 6.6 hours for 75% of the lead to decay.

Explanation:

The radioactive decay follows first order rate law

The half life and rate constant are related as

k=rate constant=\frac{0.693}{halflife}=\frac{0.693}{3.3}=0.21h^{-1}

The rate law for first order reaction is

time=\frac{1}{k}(ln[\frac{A_{0}}{A_{t}}]

Where

A0 = initial concentration = 1 g

At= final concentration = 0.25 g (as 75% undergoes decay so 25% left]

time=\frac{1}{0.21}(ln(\frac{1}{0.25})=6.6hours

5 0
3 years ago
What does a group of atoms joined by chemical bonds create?
bagirrra123 [75]

Answer:

I can say that it is not a compound because I got it wrong

Explanation:

7 0
3 years ago
Read 2 more answers
Calculating the Molecular Weight and Subunit Organization of a Protein From Its Metal Content The element molybdenum (atomic wei
Deffense [45]

Answer:

Dimer of two peptide chains with 1 mole of molybdenum metal each.

Explanation:

Percentage of molybdenum in protein = 0.08%

Molecular mass of nitrate reductase = 240,000 g

Mass of molybdenum = x

0.08\%=\frac{x}{240,000 g}\times 100=192 g

Moles of molybdenum =\frac{192 g}{95.95 g/mol}=2.00 mol

Each peptide chain of nitrate reductase contain 1 mole of molybdenum.

This means that nitrate reductase is composed of to two peptide chains. And in each peptide there is a single mole of molybdenum metal.

4 0
4 years ago
What is the ph of a 2.00 m hno2 solution if ka=5.00 e-6?
zysi [14]

Answer: -

2.5

Explanation: -

Initial [HNO₂] = 2.00 M

ka = 5.00 x 10 ⁻⁶

ICE table for HNO₂ =

[\left[\begin{array}{cccc}concentrations&HNO2&H+&NO2\\Initial&2.00&0&0\\Change&-x&+x&+x\\Equilibrium&2.00-x&x&x\end{array}\right]

Ka = \frac{x2}{2.00-x}

5.00 x 10-6 = \frac{x2}{2.00-x}

x = 0.0032 M

pH = - log [H⁺]

= - log 0.0032

= 2.5

6 0
3 years ago
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