There is a shortcut to this Chem question. simply look at this problem as if it were a cooking recipe. you have 7 parts Carbon and 18 Parts Hydrogen for a total of 25 parts. Simply divide 5.2 by 25 then multiply by 7 to get your answer.
(5.2/ 25) 7 = 1.456 moles
Energy cannot be created nor destroyed, but it changes from one form to another. Hence, option C is correct.
<h3>What is energy?</h3>
Energy is the ability to do work.
In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.
This law means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.
Hence, option C is correct.
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Answer:
The nucleus consists of 9 protons and 10 neutrons. Nine electrons occupy available electron shells.
The law which this chemist is most likely investigating heating a fixed amount of gas in a sealed glass container is: Gay Lussac’s law.
Gay Lussac's law states that when the volume of an ideal amount of gas is held (kept) constant, the pressure of the gas is directly proportional to the absolute (Kelvin) temperature of the gas.
Mathematically, Gay Lussac's law is calculated by using the formula;
<u>Where:</u>
is the original pressure.
is the final pressure.
is the original temperature.
is the final temperature.
In conclusion, the chemist is most likely investigating how changes in temperature affect the pressure of the gas by heating a fixed amount in a sealed glass container in accordance with Gay Lussac's law.
Read more: brainly.com/question/24928274
We calculate first the number of moles of CO2 and H2O produced by dividing the given masses by the molar masses of CO2 and H2O.
moles CO2 = (12.9 g CO2) x (1 mole CO2 / 12 g CO2) = 1.075 moles.
moles H2O = (6.15 g H2O) x (1 mole H2O / 18 g H2O) = 0.36 moles
Then, we count the number of C, H, and O moles. This gives us 1.075 moles C, 2.5 moles O and 0.72 moles H. The empirical formula is,
C1.075H0.72O2.5
Simplifying,
C4H3O10
