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guajiro [1.7K]
2 years ago
8

You have a 250. -ml sample of 1. 28 m acetic acid (ka = 1. 8 x´ 10–5). calculate the ph of the best buffer.

Chemistry
2 answers:
exis [7]2 years ago
7 0

The ideal buffer's pH value is 4.74..

What is best buffer ?

The Best Buffer is a buffer that has equal amounts of the weak acid and its conjugate base. It responds well to the addition of acids and bases in order to fend off pH changes. A mixture of the weak base and its conjugate acid, or the weak acid and its conjugate base, is referred to as a buffer solution.

Here weak acid is acetic acid CH3COOH

The following equation can be used to determine a buffer's pH:

pH = pka + logconjugate baseweak acid

Now, the weak acid and its conjugate base are present in equal amounts in the optimal buffer.

Therefore,

Conjugate base = weak acid

This implies that,

pH = pka + log 1

pH = pka  + 0

pH = pka

Now, pka can be written as -log ka

The value of ka is given as 1.8 * 10-5

Therefore,

pH = -log (1.8 * 10-5)

pH = 4.74

As a result, the ideal buffer has a pH of 4.74..

Learn more about the pH on

brainly.com/question/22390063

#SPJ4

Nadya [2.5K]2 years ago
4 0

The ph of the best buffer is 4.74

The given acetic acid is a weak acid

The equation of the pH of the buffer

pH = pKa + log ( conjugate base / weak acid ).

For best buffer the concentration of the weak acid and its conjugate base is equal.

pH = pKa + log 1

pH = pKa + 0

pH = pKa

given Ka = 1.8 × 10⁻⁵

pKa = - log ka

pH = -log ( 1.8 × 10⁻⁵ )

pH = 4. 74

Hence the pH of the best buffer is 4.74

Learn more about the pH on

brainly.com/question/22390063

#SPJ4

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3 years ago
The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichl
nevsk [136]

Complete Question

A student is extracting caffeine from water with dichloromethane. The K value is 4.6. If the student starts with a total of 40 mg of caffeine in 2 mL of water and extracts once with 6 mL of dichloromethane

The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichloromethane each time. How much caffeine will be in each dichloromethane extract?

Answer:

The mass of  caffeine extracted is  P =  39.8 \ mg

Explanation:

From the question above  we are told that

    The  K value is  K =  4.6

     The  mass of the caffeine is  m  = 40 mg

      The  volume of water is  V  = 2 mL

      The volume  of caffeine is  v_c =  2 mL

     The number of times the extraction was done is  n =  3

Generally the mass of  caffeine that will be  extracted is  

           P =  m  *  [\frac{V}{K *  v_c + V} ]^3

substituting values  

           P =  40   *  [\frac{2}{4.6 *  2 + 2} ]^3

           P =  39.8 \ mg

6 0
3 years ago
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