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Andru [333]
2 years ago
13

Please Please Please help + show the work please! :)

Chemistry
2 answers:
Rudiy272 years ago
7 0

Molar mass of SmO or sodium methylate is 160g/mol

Now

  • No of moles =Given mass /Molar mass

Given mass

  • No of moles ×Molar mass
  • 9.3×10^{-3}×160
  • 1.488g
Mazyrski [523]2 years ago
4 0
The gram-formula mass of Sm is 150.36 u, and the gram-formula mass of O is 15.999 u, so the gram-formula mass of SmO is about 150.36+15.999 = 160.36 g/mol.

So, there are about (9.30 * 10^-3)(160.36)=1.49 grams
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A 155.0 g piece of copper at 128 oC is dropped into 250.0 g of water at 17.9 oC. (The specific heat of copper is 0.385 J/goC.) C
Mamont248 [21]

Answer:

T_{eq}=23.85^oC

Explanation:

Hello,

In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:

\Delta H_{Cu}=-\Delta H_{H_2O}

Therefore the equilibrium temperature shows up as:

m_{Cu}Cp_{Cu}(T_{Cu}-T{eq}) = m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})\\\\T_{eq}=\frac{m_{Cu}Cp_{Cu}T_{Cu}-m_{H_2O}Cp_{H_2O}T_{H_2O}}{m_{Cu}Cp_{Cu}-m_{H_2O}Cp_{H_2O}} \\

Thus, by knowing that water's heat capacity is 4.18J/g°C, one obtains:

T_{eq}=\frac{155.0g*0.385\frac{J}{g^oC}*128^oC+250.0g*4.18\frac{J}{g^oC}*17.9^oC}{155.0g*0.385\frac{J}{g^oC}+250.0g*4.18\frac{J}{g^oC}}=23.85^oC

Best regards.

6 0
3 years ago
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What are two fungal skin infections that humans can contract?
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Ringworm and jock itch
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What are the four main parts of the Sun? *
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An aqueous solution at 27°c contains 3.6 g of a protein in a 200 ml sample. the osmotic pressure is 0.0203 atm. what is the mola
umka21 [38]
In order to calculate the molar mass of the protein, we may manipulate the ideal gas equation:
PV = nRT, where n is the number of moles. We also know that:
n = m / Mr, where m is mass and Mr is molecular weight
Thus,
Mr = (mRT)/(PV)
Here, the mass is in grams, the temperature is in Kelvin, the pressure is in atm and the volume is in liters, so the molar gas constant is 0.082057.

Mr = (3.6 * 0.082057 * (27 + 273)) / (0.0203 * 0.2)
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8 0
4 years ago
The chemical equation below shows the combustion of methane (CH4).
STatiana [176]
The correct answer is 6.15g of CO2 will be produced.

The approach to answer this question is to use the molar mass to find the number of moles of oxygen consumed. Then use the chemical equation to determine the number of moles of CO2 that would be produced (half that of oxygen). Then use the molar mass of CO2 to calculate the mass.

Mmass O2 = 32g/mol
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mass O2 consumed = 8.94g
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6 0
4 years ago
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