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Andru [333]
1 year ago
13

Please Please Please help + show the work please! :)

Chemistry
2 answers:
Rudiy271 year ago
7 0

Molar mass of SmO or sodium methylate is 160g/mol

Now

  • No of moles =Given mass /Molar mass

Given mass

  • No of moles ×Molar mass
  • 9.3×10^{-3}×160
  • 1.488g
Mazyrski [523]1 year ago
4 0
The gram-formula mass of Sm is 150.36 u, and the gram-formula mass of O is 15.999 u, so the gram-formula mass of SmO is about 150.36+15.999 = 160.36 g/mol.

So, there are about (9.30 * 10^-3)(160.36)=1.49 grams
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The reaction between sodium and chlorine that forms table salt is shown
Olegator [25]

Answer: 2 Na (s) + Cl(g) -> 2 NaCl (s)

Explanation:

7 0
3 years ago
A balloon, whose volume at 23°C is 535 mL, is heated to 46°C. Assuming the pressure and amount of gas remain constant, what is t
NikAS [45]
This problem requires a certain equation.  That equation is V1/T1=V2/T2, where V1 is your initial volume (535 mL in this case), T1 is your initial temperature in Kelvin(23 degrees C = 296 K), V2 is your final volume (unknown), and T2 is your final temperature (46 degrees C = 319 K). By plugging in these values, the equation looks like this: 535/296=V2/319.  Now multiply both sides of the equation by 319, and your final answer is V2= 576.6 mL
5 0
3 years ago
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Complete the following equations : H3PO4 = 3H+ --------------- CaSO4 = Ca 2+ ---------------- (2) b) Write the formulae of the s
jeka94

Answer:

H₃PO₄ → 3H⁺ + PO₄³⁻

CaSO₄ → Ca²⁺ + SO₄²⁻

b. CaCl₂

Explanation:

When H₃PO₄ is dissolved in water, there are produced the H⁺ and PO₄³⁻ ions. The equation is:

H₃PO₄ → 3H⁺ + PO₄³⁻

In the same way, CaSO₄ is dissolved in:

CaSO₄ → Ca²⁺ + SO₄²⁻

b. Now, in a reaction of an acid (HCl) and a base (Ca(OH)₂), water, H₂O and a salt are produced:

2 HCl + Ca(OH)₂ → 2H₂O + Salt

The ions that are not present in the reaction are Cl⁻ and Ca²⁺, the salt is CaCl₂ and the balanced reaction is:

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5 0
2 years ago
Part A:
uranmaximum [27]

Answer:

Part A = The mass of sulfur is 6.228 grams

Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams

Explanation:

Part A

Step 1: Data given

A mixture of carbon and sulfur has a mass of 9.0 g

Mass of the product = 27.1 grams

X = mass carbon

Y = mass sulfur

x + y = 9.0  grams

x = 9.0 - y

x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6

(9 - y)*(44.01/12.01) + y(64.07/32.07)

(9-y)(3.664) + y(1.998)

32.976 - 3.664y + 1.998y = 22.6

-1.666y = -10.376

y = 6.228 = mass sulfur

x = 9.0 - 6.228 = 2.772 grams = mass C

The mass of sulfur is 6.228 grams

Part B

Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).

Calculate moles of 1 silver atom

Moles = 1/ 6.022*10^23

Moles = 1.66*10^-24 moles

Mass = moles * molar mass

Mass = 1.66*10 ^-24 moles *107.87

Mass = 1.79 * 10^-22 grams

The mass of 1 silver atom is 1.79 * 10^-22 grams

5 0
2 years ago
Read 2 more answers
Which element could likely substitute for Si in a solid solution?
yulyashka [42]

Answer:aluminum

Explanation:aluminum is a precious metal which means that it can be changed into a liquid solid or gas

4 0
3 years ago
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