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2 years ago

Please Please Please help + show the work please! :)

Chemistry

2 answers:

Rudiy272 years ago

7 0

Molar mass of SmO or sodium methylate is 160g/mol

Now

No of moles =Given mass /Molar mass

Given mass

No of moles ×Molar mass
9.3×10^{-3}×160
1.488g

Mazyrski [523]2 years ago

4 0

The gram-formula mass of Sm is 150.36 u, and the gram-formula mass of O is 15.999 u, so the gram-formula mass of SmO is about 150.36+15.999 = 160.36 g/mol.

So, there are about (9.30 * 10^-3)(160.36)=1.49 grams

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How many valence electrons are in cbr2cohnh2

marishachu [46]

Answer:

36 valence electrons

Explanation:

Given CBr₂COHNH₂ => Br₂C = C - O - H

H - N - H

#Valence e⁻s = 2Br + 2C + 3H + 1N + 1O = 2(7) + 2(4) + 3(1) + 1(5) + 1(6)

= 14 + 8 + 3 + 5 + 6 = 36 valence electrons

Addendum ...

#Bonded e⁻s = 2Br + 2C + 3H + 1N + 1O = 2(8) + 2(8) + 3(2) + 1(8) + 1(8)

= 16 + 16 + 6 + 8 + 8 = 54 bonded electrons

#Covalent Bonds = #Valence e⁻ - #Bonded e⁻ / 2 = (54 - 36) / 2 = 9 cov. bonds.

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3 years ago

What part of the scientific method involves controlling variables while testing a hypothesis?

Angelina_Jolie [31]

Answer:

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Explanation:

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3 years ago

A food product contains 15 g of carbohydrates, 5 g of protein and 4 g of fat. How many calories are in one serving of this produ

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Explanation:

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Read 2 more answers

Anthony needs to make a solution with a concentration of 2.5m. He begins with 2.0 iters and a 8.0M solution. What final volume d

FrozenT [24]

Answer:

The final volume is 6.4 L.

Explanation:

Dilution is reducing the concentration of a chemical and is achieved by adding more solvent to the same amount of solute. In other words, dilution is the procedure that is followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent.

In a dilution the amount of solute does not vary, and as only more volume (and mass) of solvent is being added, the concentration of the solute decreases.

In a dilution the expression is used:

Ci*Vi = Cf*Vf

where:

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

In this case:

Ci: 8 M
Vi: 2 L
Cf: 2.5 M
Vf: ?

Replacing:

8 M* 2 L= 2.5 M* Vf

Solving:

$Vf=\frac{8 M* 2 L}{2.5 M}$

Vf=6.4 L

<u><em>The final volume is 6.4 L.</em></u>

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