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AveGali [126]
3 years ago
11

A current of 1.41 A in a long, straight wire produces a magnetic field of 5.61 uT at a certain distance from the wire. Find

Physics
1 answer:
pshichka [43]3 years ago
4 0

Answer:

0.050 m

Explanation:

The strength of the magnetic field produced by a current-carrying wire is given by

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0=4\pi \cdot 10^{-7} H/m is the vacuum permeability

I is the current in the wire

r is the distance from the wire

And the magnetic field around the wire forms concentric circles, and it is tangential to the circles.

In this problem, we have:

I=1.41 A (current in the wire)

B=5.61\mu T=5.61\cdot 10^{-6} T (strength of magnetic field)

Solving  for r, we find the distance  from the wire:

r=\frac{\mu_0 I}{2\pi B}=\frac{(4\pi \cdot 10^{-7})(1.41)}{2\pi (5.61\cdot 10^{-6})}=0.050 m

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An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pip
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Answer:

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Explanation:

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   The velocity at location 1 is  v_1 =  2.4 \  m /s

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=>     A_1 =  \pi *  \frac{0.88^2}{ 2}

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Generally the area at location 1 is  

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Generally from continuity equation we have that

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=>   1.2166 *   2.4   =  0.528   * v_2

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Answer:

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Explanation:

Applying,

ω = θ/t.............. Equation 1

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From the question,

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