Answer:
a) T1 = 7.48 N
b) T2 = 18.09N
c) I = 0.0115 kgm^2
Explanation:
Mass of textbook= 2.08kg
Diameter of cord = 0.130m
Radius = 0.130/2 = 0.065m
Distance = 1.30m
Time interval = 0.830 sec
From equation of motion,
S = ut + 1/2at^2
U = initial velocity = 0
S = 1/2at^2
2S = at^2
a = 2S/t^2
a = 2(1.3) / 0.830^2
a = 3.77 m/s^2
T1 = m1*a ..........(1)
m2g - T2 = m2a..........(2)
T1 = (2.08)(3.77)
T1 = 7.84N
m2g - T2 = m2a
T2 = m2g - m2a
T2 = m2(g - a)
T2 = 3(9.80 - 3.77)
T2 = 3(6.03)
T2 = 18.09N
Moment of inertia (I)
I = [(T2 - T1) r^2]/a
I = [(18.09 - 7.84)(0.065)^2]/ 3.77
I = (10.25)(0.065)^2 / 3.77
I = 0.0115 kgm^2
Explanation:
In brief, electrons are negative charges and protons are positive charges. An electron is considered the smallest quantity of negative charge and a proton the smallest quantity of positive charge.
Two negative charges repel. Also, two positive charges repel. A positive charge and a negative charge attract each other (all experimentally verified.)
Point Charge: An accumulation of electric charges at a point (a tiny volume in space) is called a point charge.
Note: When an atom loses an electron, the separated electron forms a negative charge, but the remaining that contains one less electron or consequently one more proton becomes a positive charge. A positive charge is not necessarily a single proton. In most cases, a positive charge is an atom that has lost one or more electron(s).
Answer:
6.4 Joules
Explanation:
For springs, Hooke's law states that;
F = ke
where F is a force applied, e is the extension and k is the spring constant.
Work done in a spring is the same as the potential energy stored in the spring. So that;
Work done = k
e = -
= 4 cm = 0.4 m
= 0
So that,
- = 0.4 m
Thus,
Work done = x 80 x
= 40 x 0.16
= 6.4
Work done = 6.4 J
The work done by the force on the spring is 6.4 Joules.
The sign associated with the average velocity of the object is negative.
<h3>
Average velocity of the object</h3>
The average velocity of the object is calculated as follows;
Average velocity = (v1 + v2)/2
v1 = -20/30 = -0.667 m/s
v2 = 20/50 = 0.4 m/s
Average velocity = (-0.667 + 0.4)/2
Average velocity = -0.134 m/s
Thus, the sign associated with the average velocity of the object is negative.
Learn more about average velocity here: brainly.com/question/6504879
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