A charged particle moving in a magnetic field experiences a force equal to:
Thus, the magnitude of the force that the proton experiences is given by:
The magnetic field is perpendicular to the proton's velocity, therefore, we have 
. Replacing the given values, we obtain:
Answer:
Gina should put “rubber tires” under “Synthetic.”
Gina should put “starch” under “Natural.”
Explanation: I just did the assignment ;P
Transverse waves. Direction of vibration of the particles is at right angles to direction of movement.
Answer:
power=work done÷time taken
2×5=10
10÷10=1
ans 1J per second
Use kinematic equations to solve:
1) yf = yo + vo*t + 1/2at²
yf = final height
yo = initial height
vo = initial velocity
a = acceleration
t = time
yf - yo = vo*t + 1/2at²
yf - yo = h
vo = 0
Thus,
h = 1/2at²
h = 1/2(9.8)(12)² = 705.6 m
2) vf = vo + at
vo = 0
Thus,
vf = at
vf = (9.8)(12) = 117.6 m/s
